What is an equation of the line that passes through the points (2, -2) and (8, 4)?
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Answer:
Step-by-step explanation:
We are given;
- The equation of a line 6x-2y=4+6y
- A point (8, -16)
We are required to determine the equation of a line parallel to the given line and passing through the given point.
- One way we can determine the equation of a line is when we are given its slope and a point where it is passing through,
First we get the slope of the line from the equation given;
- We write the equation in the form y = mx + c, where m is the slope
That is;
6x-2y=4+6y
6y + 2y = 6x-4
8y = 6x -4
We get, y = 3/4 x - 4
Therefore, the slope, m₁ = 3/4
But; for parallel lines m₁=m₂
Therefore, the slope of the line in question, m₂ = 3/4
To get the equation of the line;
We take a point (x, y) and the point (8, -16) together with the slope;
That is;
Thus, the equation required is
Here you go, hope I helped.
