Question

I don't understand this radical

Answer 1

$\bf -\sqrt{28q}\cdot -\sqrt{99q}\implies \stackrel{\textit{recall } minus\cdot minus=plus}{\sqrt{28q}\cdot \sqrt{99q}}~~ \begin{cases} 28=2\cdot 2\cdot 7\\ \qquad 2^2\cdot 7\\ 99=3\cdot 3\cdot 11\\ \qquad 3^2\cdot 11 \end{cases} \\\\\\ \sqrt{2^2\cdot 7q}\cdot \sqrt{3^2\cdot 11q}\implies 2\sqrt{7q}\cdot 3\sqrt{11q}\implies 6\sqrt{7q\cdot 11q} \\\\\\ 6\sqrt{77q^2}\implies 6q\sqrt{77}$

Answer 2

Below are the steps and answer to this problem