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VashaNatasha [74]
3 years ago
6

Translate each of the following English statements into logical expressions. The domain of discourse is the set of all real numb

ers.
(a) There are two numbers whose ratio is less than 1.
(b) The reciprocal of every positive number is also positive.
(c) There are two numbers whose sum is equal to their product.
(d) The ratio of every two positive numbers is also positive.
(e) The reciprocal of every positive number less than one is greater than one.
(f) There is no smallest number.
(g) Every number besides 0 has a multiplicative inverse.
(h) Every number besides 0 has a unique multiplicative inverse.
Mathematics
1 answer:
Scilla [17]3 years ago
4 0

Answer:

A) З x,y : ( x/y < 1,  y/x < 1 )

B) ∀ Y : ( Y > 0 = 1/Y > 0 )

C) з x,y : ( x+y = xy )

D) ∀ x,y : [ ( x>0 ) ∧( y > 0 ) = (( x/y > 0 ) ∧ ( y/x > 0 ))

E ) ∀ y : [ ( y > 0 ) ∧ ( y < 1) = ( 1 / y > 1 )

F) <em>n</em> ( ( з x ∀ y ( x <y ) )

G) ∀x (( x ≠ 0 ) = ( зy ( xy = 1 ) ))

H) ∀x ( (x≠0) = ( з! y (xy = 1))

Step-by-step explanation:

since the domain of discourse is a set of all real numbers the logical expressions of the English statements are expressed with respect to real number:

A) З x,y : ( x/y < 1,  y/x < 1 )

B) ∀ Y : ( Y > 0 = 1/Y > 0 )

C) з x,y : ( x+y = xy )

D) ∀ x,y : [ ( x>0 ) ∧( y > 0 ) = (( x/y > 0 ) ∧ ( y/x > 0 ))

E ) ∀ y : [ ( y > 0 ) ∧ ( y < 1) = ( 1 / y > 1 )

F) <em>n</em> ( ( з x ∀ y ( x <y ) )

G) ∀x (( x ≠ 0 ) = ( зy ( xy = 1 ) ))

H) ∀x ( (x≠0) = ( з! y (xy = 1))

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