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matrenka [14]
3 years ago
8

In a Senate Legislature, there were 119 more members in the House of Representatives than in the Senate. If there were m members

in the Senate, write an expression to represent the total members in the State Legislature.
Mathematics
1 answer:
sesenic [268]3 years ago
6 0
It is very important to go through the details given in the question. Based on those given details the answer to the question can be easily deduced.
The number of members in the senate = m
Then
The number of members in the House of Representatives = m + 119
So
The total number of members in the State Legislature = m + m + 119
                                                                                       = 2m + 119
From the above deduction we an conclude that there are 2m + 119 members in total in the state Legislature. I hope there is nothing complicated in the procedure for you to understand.
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No. At a significance level of 0.01, there is not enough evidence to support the claim that the average number of sick days a worker takes per year is significantly less than 5.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average number of sick days a worker takes per year is significantly less than 5.

Then, the null and alternative hypothesis are:

H_0: \mu=5\\\\H_a:\mu< 5

The significance level is 0.01.

The sample has a size n=30.

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The standard deviation of the population is known and has a value of σ=1.2.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.2}{\sqrt{30}}=0.219

Then, we can calculate the z-statistic as:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{4.8-5}{0.219}=\dfrac{-0.2}{0.219}=-0.913

This test is a left-tailed test, so the P-value for this test is calculated as:

\text{P-value}=P(z

As the P-value (0.181) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.01, there is not enough evidence to support the claim that the average number of sick days a worker takes per year is significantly less than 5.

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Answer:

Please find the graph in the attached file.

Step-by-step explanation:

\to \frac{\frac{4}{10}}{2} \ and \ \frac{1}{2} \times \frac{4}{10} =\frac{2}{10}\\\\\to \frac{0.4}{2} \ and \  0.5 \times 0.4 =0.2\\\\\to 0.2 \ and \ 0.2 =0.2\\\\ \to \frac{2}{10} \ and \  \frac{2}{10} = \frac{2}{10}\\\\

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3 years ago
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