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3 years ago

If the perimeter of a square field measures 440 yards , what is the length of each side ?

Mathematics

2 answers:

NARA [144]3 years ago

7 0

Since it is a square, all sides are equal.
Divide the 440 by 4 to find the length of each side.
440/4 = 110 yards

Nonamiya [84]3 years ago

7 0

A couple of things we need to keep in mind before we determine the sides of the field.
1) The field is square. This is important because a square has four equal sides; not one side can be different with a square.

2) The full perimeter is 440 yards.

Since we know that a square has a perimeter of 440 yards, we can use this information to find the length of each side.
A square has four equal sides, so we can divide 440 by 4 (since the perimeter is all of the sides' lengths added together) and we would have the length of one, and if we have the length of one (the lengths are all equal), we have the length of all four.

As so:

440 / 4 = 110
So, the lengths of the sides are 110. To check if this is true, we can draw a square and input the length of 110 for all four of them.

(I can't draw on here...so we have 4 sides of 110.)

110 + 110 + 110 + 110 = 440!

Now, we know our answer is correct!
Hope I could help you out! If my math is incorrect, or I provided an answer you were not looking for, please let me know! However, if you think my math was explained well, please consider marking my answer as <em>Brainliest! </em>:)

Have a good one.
God bless!

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Mashcka [7]

Answer:

a) P' = P

$P(t) = 24e^{0.693t}$ where t is step of 6 months

b) 7.7 years

c)1064.67 rabbits/year

Step-by-step explanation:

The differential equation describing the population growth is

$\frac{dP}{dt} = P$

Where t is the range of 6 months, or half of a year.

P(t) would have the form of

$P(t) = P_0e^{kt}$

where $P_0 = 24$ is the initial population

After 6 month (t = 1), the population is doubled to 48

$P(1) = 24e^k = 48$

$e^k = 2$

$k = ln(2) = 0.693$

Therefore $P(t) = 24e^{0.693t}$

where t is step of 6 months

b. We can solve for t to get how long it takes to get to a population of 1,000,000:

$24e^{0.693t} = 1000000$

$e^{0.693t} = 1000000 / 24 = 41667$

$0.693t = ln(41667) = 10.64$

$t = 10.64 / 0.693 = 15.35$

So it would take 15.35 * 0.5 = 7.7 years to reach 1000000

c. $P' = P_0ke^{kt}$

We need to resolve for k if t is in the range of 1 year. In half of a year (t = 0.5), the population is 48

$24e^{0.5k) = 48$

$0.5k = ln2 = 0.693$

$k = 1.386$

Therefore, $P' = 1.386*24e^{1.386t}$

At the mid of the 3rd year, where t = 2.5, we can calculate P'

$P' = 1.386*24e^{1.386*2.5} = 1064.67$ rabbits/year

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Answer:

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