Long division x^3 - 6x^2 + 13x -12 over x

irakobra [83]

LGN I believe. If you look at how the ret part of the match corresponds with the next match, you can correspond the letters based on the other triangles.

7 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

2 years ago

Jean Claude took out a $3,500 installment loan at 11% for 12 months. His monthly payments were $309.34. After seven payments, th

bezimeni [28]

$27.86 is the answer

5 0

3 years ago

Read 2 more answers

Amistad deposited $2,163.27 in a savings account that earns 3.9% simple interest. What will Amistad's account balance be in nine

avanturin [10]

Given that Amistad deposited $2,163.27 in a savings account that earns 3.9% simple interest.

That means we need to use Simple interest formula to find the Amistad's account balance in nine months.

Simple interest formula is

A=P(1+RT)

Where P= principal amount = $2163.27

R= rate of interest = 3.9%= 0.039

T= time in years = 9 months = 9/12 years = 0.75

Now plug these values into above formula:

A=2163.27(1+0.039* 0.75)

A=2163.27(1+0.02925)

A=2163.27(1.02925)

A=2226.5456475

Hence Amistad's account balance in nine months will be approx $2226.55

8 0

3 years ago

There is 1/4 chance of picking a green marble from a bag. IF there are 20 total marbles in the bag, how many marbles must be gre

matrenka [14]

Answer:

5 green marbles.

Step-by-step explanation:

20* 1/4 = 5

8 0

3 years ago

Long division x^3 - 6x^2 + 13x -12 over x - 3