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Snowcat [4.5K]
2 years ago
6

Find the equation of a line that has the same slope as y = 6 - 2x and the same y-intercept as y= "-10x" – 4.

Mathematics
2 answers:
Tresset [83]2 years ago
4 0

Step-by-step explanation:

slope of y=6-2x=> -2 as it is in the form (y=mx+c )

y intercept of y=-10x-4=-4(as it in the form y=mx+c ,c is intercept made by y-axis)

so equation of line having-4 as y intercept and slope as -2 will be given by (intercept slope form):

that is y=mx+c

=> y= -2x-4=> 2x+y+4=0 is equation of required line

Mkey [24]2 years ago
3 0

Answer:

y = - 2x - 4

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 6 - 2x = - 2x + 6 ← is in slope- intercept form

with slope m = - 2

y = - 10x - 4 ← is in slope- intercept form

eith y- intercept c = - 4

then

y = - 2x - 4 ← is the equation of the required line

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Express 45 minutes as a fraction of 1 hour ​
Pepsi [2]

Answer:

\frac{3}{4}

Step-by-step explanation:

There are 60 minutes in 1 hour

To express as a fraction

\frac{45}{60}

Divide numerator/denominator by 15

\frac{45}{60} = \frac{3}{4}

8 0
3 years ago
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
Solve the following equation.-3 = x/5
Umnica [9.8K]
I hope this helps you




x/5= -3



x= -3.5



x= -15
7 0
3 years ago
f the length of side a is 12 centimeters, m= 36°, and m= 75°, what is the length of side b? Round your response to two decimal p
-Dominant- [34]

Answer:

Option C. is correct

Step-by-step explanation:

In the triangle ABC, vertices are A(12, 8), B(4, 8) and C(4, 14)

AB =

BC =

AC =

In triangle XYZ vertices are X(6,6), Y(4,12) and Z(10, 14)

XY =

YZ =

XZ =

In triangle MNO, vertices are M(4, 16), N(4, 8) and O(-2, 8)

MN =

MO =

NO =

In triangle JKL, vertices are J(14, -2), K(12,2) and L(20, 4)

JK =

KL =

JL =

Now we compare the sides for the congruence

Since AB = MN = 8

BC = NO = 6

AC = OM = 10

So ΔABC ≅ Δ MNO

Option C. is correct

Read more on Brainly.com - brainly.com/question/1747695#readmore

3 0
2 years ago
What is the weight of a 32 kg child
sattari [20]

Answer:

32 kgs ?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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