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77julia77 [94]
3 years ago
12

Use the given data to find the minimum sample size required to estimate a population proportion or percentage. Margin of​ error:

nine percentage​ points; confidence level 95​%; from a prior​ study, p with caret is estimated by the decimal equivalent of 38​%.
Mathematics
1 answer:
Yakvenalex [24]3 years ago
6 0

Answer: 112

Step-by-step explanation:

Given : Significance level : \alpha=1-0.95=0.05

Critical value: z_{\alpha/2}=1.96

Margin of error : E = 9%=0.09

The estimated proportion of caret : p =0.38

Now, the formula to find the sample size :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2

i.e. n=(0.38)(1-0.38)(\dfrac{1.96}{0.09})^2

=111.738390123\approx112

Hence, the required minimum sample size = 112

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