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makkiz [27]
4 years ago
11

If a movie ticket cost $10 in 2016, what was its price in 1980

Mathematics
1 answer:
zaharov [31]4 years ago
8 0

Answer:

It would be in the $3.30 or lower zone

Step-by-step explanation:

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Approximately 12.6% of all (untreated) Jonathan apples had bitter pit in a study conducted by the botanists Ratkowsky and Martin
bagirrra123 [75]

Answer:

Step-by-step explanation:

Let n be a random variable that represents the first Jonathan apple chosen at random that has bitter pit.

a) P(X = n) = q(n-1)p, where q = 1 - p.

From the information given, probability if success, p = 12.6/100 = 0.126

b) for n = 3, the probability value from the geometric probability distribution calculator is

P(n = 3) = 0.096

For n = 5, the probability value from the geometric probability distribution calculator is

P(n = 5) = 0.074

For n = 12, the probability value from the geometric probability distribution calculator is

P(n = 12) = 0.8

c) For n ≥ 5, the probability value from the geometric probability distribution calculator is

P(n ≥ 5) = 0.58

d) the expected number of apples that must be examined to find the first one with bitter pit is the mean.

Mean = 1/p

Mean = 1/0.126 = 7.9

Approximately 8 apples

7 0
4 years ago
Don works in home construction. He determined that the function t(A)=144A/9.252 gives the total number of 9 in. tiles needed to
Drupady [299]

Answer:

Step-by-step explanation:

It’s easy

7 0
3 years ago
The researcher has limited resources. He sends 9 emails from a Latino name, and 14 emails from a non-Latino name. For the Latino
deff fn [24]

Answer: 38.41 minutes

Step-by-step explanation:

The standard error for the difference in means is given by :-

SE.=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2}}

where , \sigma_1 = Standard deviation for sample 1.

n_1= Size of sample 1.

\sigma_2 = Standard deviation for sample 2.

n_2= Size of sample 2.

Let the sample of Latino name is first and non -Latino is second.

As per given , we have

\sigma_1=82

n_1=9

\sigma_2=101

n_2=14

The standard error for the difference in means will be :

SE.=\sqrt{\dfrac{(82)^2}{9}+\dfrac{(101)^2}{14}}

SE.=\sqrt{\dfrac{6724}{9}+\dfrac{10201}{14}}

SE.=\sqrt{747.111111111+728.642857143}

SE.=\sqrt{1475.75396825}=38.4155433158\approx38.41

Hence, the standard error for the difference in means =38.41 minutes

3 0
3 years ago
What is the approximate area of the following circle?
balu736 [363]

Answer:

38.47 {m}^{2}

Step-by-step explanation:

The formula to find the area of a circle is

a= \pi {r}^{2}

We know that

\pi = 3.14 \:  \:  \:  \:  \:  \: r = 3.5

Therefore the area is

a= \pi {r}^{2} \\ \\ a = (3.14) {(3.5)}^{2} \\ \\ a = 3.14 \times 12.25 \\ \\ a = 38.47 {m}^{2}

8 0
2 years ago
Read 2 more answers
Can anyone help? <br><br> If arcLM = 8x-56 and arcNP = 5x+22, find arcLP.
Mashcka [7]

Answer:

arcLP = 19

Step-by-step explanation:

Given the following

arcLM = 8x-56

arcNP = 5x+22

Required

arcLP

Given that arcLM = arcNP

8x-56 = 5x+22

8x - 5x  = 22 + 56

3x = 78

x = 78/3

x = 26

Let assume arcLP = x - 7

arcLP = 26 -7

arcLP = 19

4 0
3 years ago
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