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eduard
3 years ago
13

A sociologist studying freshmen carried out a survey, asking, among other questions, how often students went out per week, how m

any hours they studied per day, and how many hours they slept at night.
The tables provide the answers on the time slept and the time spent studying by whether or not students went out.

Go out Hours/day studied Hours slept less than 6 Hours slept 6 or more Total Stay in dorm Hours/day studied Hours slept less than 6 Hours slept 6 or more Total Less than 2 3 9 12 Less than 2 40 120 160 2 or more 14 14 28 2 or more 20 20 40 Total 17 23 40 Total 60 140 200

When we examine the data, we find that students who studied more slept less, both among those who go out and among those who stay in the dorm.

When we combine both groups of students, we find that those who studied more also slept more.

This is an example of:

a. Simpson's Paradox.

b. Andersen's Paradox.

c. the Probability Paradox.

d. the Gaussian Paradox.
Mathematics
1 answer:
IgorC [24]3 years ago
4 0

Answer:

This is called Simpson's Paradox.

Therefore the correct option is A.) Simpson's Paradox.

Step-by-step explanation:

i) This is called Simpson's Paradox.

ii) If there are trends that tend to appear in several different groups of data which apparently either disappear or tend to reverse when these data groups are combined.

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A jar of peanut butter holds 40 ounces. When you make a sandwich, you use two ounces. Which equation best represents the amount
Elodia [21]
2 ounces each sammich made
x=number of sammiches made
y=amount left

amount left=full-gotten
y=40-2 times number of sammiches
y=40-2x
or
y=-2x+40

D is da answer
6 0
4 years ago
Suppose that 3 balls are chosen without replacement from an urn consisting of 5 white and 8 red balls. Let Xi equal 1 if the ith
Katarina [22]

Answer:

The joint probability mass function table is provided below.

Step-by-step explanation:

The experiment consist of drawing 3 balls from an urn containing 5 white and 8 red balls.

The random variable <em>Xi</em> is defined as follows:

<em>Xi</em> = 1; if the ith ball is white

<em>Xi</em> = 0; otherwise.

Then <em>X</em>₁ = the 1st ball is white and <em>X</em>₂ = the 2nd ball is white.

The sample space is as follows:

S = {(X₁ = 0, X₂ = 0), (X₁ = 0, X₂ = 1), (X₁ = 1, X₂ = 0), (X₁ = 1, X₂ = 1)}

Compute the probability of each event in the sample space as follows:

P(X_{1} = 0, X_{2}= 0)=\frac{8}{13} \times\frac{7}{12}=\frac{14}{39}

P(X_{1} = 0, X_{2}= 1)=\frac{8}{13} \times\frac{5}{12}=\frac{10}{39}

P(X_{1} = 1, X_{2}= 0)=\frac{5}{13} \times\frac{8}{12}=\frac{10}{39}

P(X_{1} = 1, X_{2}= 1)=\frac{5}{13} \times\frac{4}{12}=\frac{5}{39}

The joint probability mass function table is provided below.

4 0
3 years ago
You have space in your garden for 60 small flowering bulbs. Crocus bulbs cost $0.25 each and daffodil bulbs cost $0.65 each. You
Doss [256]

Answer:

32 daffodils bulbs and 28 crocus bulbs

Step-by-step explanation:

Assuming 'x' as Crocus and 'y' as daffodil. Now we'll form equations.

-> for 60 small flowering bulbs

x+y=60

x=60-y --->eq(1)

->Crocus bulbs cost $0.25 each and daffodil bulbs cost $0.65 each with the budget $27.80

0.25x + 0.65y = 27.80  -->eq(2)

Next is to substitute x=60-y in eq(2)

(2)=>0.25(60-y) + 0.65y = 27.80

15 - 0.25y + 0.65y = 27.80

0.4y = 12.8

y = 12.8/ 0.4

y= 32 daffodil bulbs

Now, plugging the value of y in eq(1)

(1)=>x=60-32

x= 28

x=28 crocus bulbs

Therefore, you can buy 32 daffodils bulbs and 28 crocus bulbs

6 0
3 years ago
Which is greater 73% of 87 or 87% of 73
blagie [28]
87% of 73 I'm guessing rn
6 0
4 years ago
Read 2 more answers
Dave grew 24 plants with 3 seed packets. How many seed packets does Dave need to have a total of 40 plants in his backyard? Assu
julsineya [31]
24/3 = 8
40/8 = 5
the answer is 5 packets
4 0
3 years ago
Read 2 more answers
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