Answer:
Code is completed below
Explanation:
Source Code in Java:
class Parenthesis
{
boolean hasBalancedParentheses(String eq) //method to check and return if a set of parenthesis is balanced or not
{
int count=0; //to store count of current unclosed opening brackets
for(int i=0;i<eq.length();i++)
{
if(eq.charAt(i)=='(')
count++;
else if(eq.charAt(i)==')')
count--;
if(count<0) //if count falls below zero, there were more closing brackets than opening brackets till this point
return false;
}
if(count>0) //if count is still more than zero, there were less closing brackets than opening brackets
return false;
return true; //if program reaches this point, it has passed all the tests
}
public static void main(String args[])
{
//testing the function
Parenthesis ob=new Parenthesis();
System.out.println(ob.hasBalancedParentheses("()(()())((())())"));
System.out.println(ob.hasBalancedParentheses(")((()())(()))())"));
}
}
Answer:
A. This algorithm needs only one pass through a data set.
Explanation:
In computing, a one-pass algorithm is a streaming algorithm which reads its input exactly once, in order, without unbounded buffering. A one-pass algorithm generally requires O(n) (see 'big O' notation) time and less than O(n) storage (typically O(1)), where n is the size of the input.
-our input is the dataset
BTW: pls give BRAINLIEST!
Answer:
Explanation:
In addition to methodology, requirements, design, analysis, implementation, prototyping, and verification, Branson and Herness (1993) assert that the object-oriented development process architecture must also address elements such as reuse, CASE tools, integration, build and test, and project management.
The options are;
A) Data
B) Front Office
C) Core Processing
D) Experience
Answer:
D) Experience
Explanation:
Under enterprise resource planning platform, experience is the process whereby vendors interact and also manage the entire supply chain link on behalf of a retail client.
Thus, option D is the correct answer
Answer:
a) Yes
b) Yes
c) Yes
d) No
e) Yes
f) No
Explanation:
a) All single-bit errors are caught by Cyclic Redundancy Check (CRC) and it produces 100 % of error detection.
b) All double-bit errors for any reasonably long message are caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit. It also produces 100 % of error detection.
c) 5 isolated bit errors are not caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit since CRC may not be able to catch all even numbers of isolated bit errors so it is not even.
It produces nearly 100 % of error detection.
d) All even numbers of isolated bit errors may not be caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit. It also produces 100 % of error detection.
e) All burst errors with burst lengths less than or equal to 32 are caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit. It also produces 100 % of error detection.
f) A burst error with burst length greater than 32 may not be caught by Cyclic Redundancy Check (CRC) during the transmission of 1024 bit.
Cyclic Redundancy Check (CRC) does not detect the length of error burst which is greater than or equal to r bits.