Answer:
The client traction weights are resting on the floor.
Explanation:
The immediate action of the nurse should be to reapply the weights to give traction to the fracture. The health care provider must be notified that the weights were lying on the floor, and the client should be realigned in bed. The client's blood pressure is slightly elevated; this could be related to pain and muscle spasms resulting from lack of pressure to reduce the fracture. Oozing of clear fluid is normal, as is the capillary refill time.
DIF: Applying/Application REF: 1060 KEY: Fracture| traction
MSC: Integrated Process: Communication and Documentation
NOT: Client Needs Category: Safe and Effective Care Environment: Management of Care
Answer:
Independent - Water/Type of water (salt and pure)
Dependent - Height of plant
Controlled - Amount of water
Explanation:
Independent is what the experimenter manipulates (in this case being the type of water.)
Dependent is what the experimenter measures and is a result of the independent (in this case being the height of plant)
Controlled is what you are trying to keep the same (in this case the amount of water you give each plant.)
<span>By rebonding with another phosphate molecule through oxidative phosphorylation, it becomes recharged and the ADP to ATP process can be restarted. This allows for more cellular energy to be produced, and more metabolic actions to be undertaken. This is the major aspect of cell respiration.</span>
Answer:
C)Parental: 41% Dr, 41% dR; recombinant: 9% DR, 9% dr.
Explanation:
The notation Dr/dR for genotypes means that one homologous chromosome has the alleles Dr and the other homologous chromosome has the alleles dR.
The heterozygous plant Dr/dR will produce 4 types of gametes: two identical to the chromosmes the individual has in its somatic cells (called parental), and two gametes which will be a mix of the alleles in the homologous chromosomes (called recombinant).
- Dr: parental
- dR: parental
- DR: recombinant
- dr: recombinant
To calculate the frequency of each type of gamete, we must use the formula:
Distance (map units) / 100 = frequency of recombination.
18 mu / 100 = 0.18.
The total frequency of recombination between the genes D and R is 0.18, but every time crossing over happens, two recombinant gametes are generated. Therefore, each recombinant gamete will have a frequency of 0.18/2=0.09 = 9%.
The frequency of parental gametes will be:
1 - frequency of recombinant gametes
1 - 0.18 = 0.82
But there are 2 parental gametes, so each of them will have a frequency of 0.82/2=0.41 = 41%.
<span>There is more sugar on side B the water to sugar ratio is lower so the water from side A will balance out the ratios between side A and B by moving across the membrane because </span>the sugar molecules cannot diffuse through the membrane, the water has to go to the sugar, therefore, we have to lower the concentration of the sugar.
