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Dvinal [7]
3 years ago
12

A company uses 4 pounds of resource 1 to make each unit of X1 and 3 pounds of resource 1 to make each unit of X2. There are only

150 pounds of resource 1 available. Which of the following constraints reflects the relationship between X1, X2 and resource 1? a) 4X, +3X2 ge 150 b) 4X,+3X2 le 150 c) 4 X, + 3 X2 = 150 d) 4X1 le 150
Mathematics
1 answer:
liraira [26]3 years ago
5 0

Answer:

b)

Step-by-step explanation:

4X1 + 3X2 less than or equal to 150

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-6r+5
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A small business assumes that the demand function for one of its new products can be modeled by p = Cekx. When p = $40, x = 1000
Maru [420]

Answer:

C= 82.1116

k=-0.0007192

Step-by-step explanation:

p=Ce^{kx}\\40=Ce^{k1000}\\30=Ce^{k1400}\\

Applying logarithmic properties yields in the following linear system:

ln(40) = ln(C) + 1000k\\ln(30) = ln(C) + 1400k

Solving for k:

ln(40) = ln(C) + 1000k\\ln(30) = ln(C) + 1400k\\400 k = ln(30)-ln(40)\\k=-0.0007192

Solving for C:

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3 years ago
A manufacturer has been selling 1400 television sets a week at $450 each. A market survey indicates that for each $21 rebate off
GuDViN [60]

Correct question is;

A manufacturer has been selling 1400 television sets a week at $450 each. A market survey indicates that for each $21 rebate offered to a buyer, the number of sets sold will increase by 210 per week

A) Find the demand function (price p as a function of units sold x).

p(x)=______

(B) How large a rebate should the company offer the buyer in order to maximize its revenue?

$=_____

Answer:

A) p(x) = (-1/10)x + 590

B) Rebate = $170

Step-by-step explanation:

A) We are told that p(x) is the demand function and x is the number of TV sets sold per week.

Now, since for each $21 rebate offered, the number of sets sold increases by 210 per week, it means that the slope here of this demand function is; m = -21/210 = -1/10

Now, he has been selling 1400 TV sets a week at $450 each. This means; p(1400) = $450

Thus, the demand function will be;

p(x) - 450 = (-1/10)(x - 1400)

Expanding the RHS;

p(x) - 450 = (-1/10)x + 140

Add 450 to both sides to get;

p(x) = (-1/10)x + 140 + 450

p(x) = (-1/10)x + 590

B) Formula for revenue is;

R = price × quantity sold

Our demand function is p = (-1/10)x + 590

Making x the subject, we have;

x = 5900 - 10p

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Thus,

R = p(5900 - 10p)

R = 5900p - 10p²

Maximum price will occur at dR/dP = 0

Thus;

dR/dP = 5900 - 20p

At dR/dP = 0,we have;

20p = 5900

p = 5900/20

p = $280

Thus, rebate = 450 - 280 = $170

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