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olga nikolaevna [1]
3 years ago
12

Plz help guys! I will mark everyone who answers correctly for each one! Plz!

Mathematics
2 answers:
max2010maxim [7]3 years ago
6 0

Answer:

Sam: 9, Amy: 13

Step-by-step explanation:

So five years ago, lets say Sam was 4, and Amy was 8. That would be half Amy's age. If we add on 5 to Sams age, as it says, Amy would then be 13, and Sam would be 9. This is also four years apart. Thus, the answers are Sam: 9 and Amy: 13

ryzh [129]3 years ago
5 0

Answer:

Let's say that x is sam's age and y is Amy's age

x=y-4

and five years ago:

x-5=(y-5)/2

y-4-5=(y-5)/2

2y-18=y-5

y=13

x=9

then:

sam's age is 9 and Amy's age is 13

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Which of the following is a perfect square trinomial?
yanalaym [24]
Your answer is D. 16x² - 56xy + 49y².

A perfect square trinomial is the result of a squared binomial, like (a + b)². Using this example, the perfect square trinomial would be a² + 2ab + b², as that is what you get when you expand the brackets.

Therefore, to determine which of these is a perfect square trinomial, we have to see if it can be factorised into the form (a + b)².

I did this by first square rooting the 16x² and 49y² to get 4x and 7y as our two terms in the brackets. We automatically know the answer isn't A or B as you cannot have a negative square number.

Now that we know the brackets are (4x + 7y)², we can expand to find out what the middle term is, so:

(4x + 7y)(4x + 7y)
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So we know that the middle number is 56xy. Now we assumed that it was (4x + 7y)², but the same 16x² and 49y² can also be formed by (4x - 7y)², and expanding this bracket turns the +56xy into -56xy, forming option D, 16x² - 56xy + 49y².

I hope this helps!
6 0
3 years ago
Read 2 more answers
Use a half-angle identity to find the exact value
Tatiana [17]

Given:

\cos 15^{\circ}

To find:

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Using fraction rule: \frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}

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Apply radical rule: \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}

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Using \sqrt{4} =2:

           $=\frac{\sqrt{2+\sqrt{3}}}{2}

$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}

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