First, solve the given system of linear equations.
Second, multiply the first equation by 4 (which was an arbitrary choice). Add your result to the 2nd equation.
You should now have the following:
First equation: No change: <span>2x + 7y = 1
Second equation: 4(</span><span>-3x – 4y = 5) = -12x -16y = 20
Solve this new system of linear equations. Do you (or do you not) obtain the same solution as your earlier one?</span>
Get a C once every two quarters and you’ll pass my guy
The first two were negative integers and the quotient is therefor a positive integer (Two negatives equal a positive)
X=-5 and y=1
you would replace the letter x or y with zero to find the intercept.
