First, solve the given system of linear equations.
Second, multiply the first equation by 4 (which was an arbitrary choice).  Add your result to the 2nd equation.
You should now have the following:
First equation:  No change:             <span>2x + 7y = 1
Second equation:  4(</span><span>-3x – 4y = 5) = -12x -16y = 20
Solve this new system of linear equations.  Do you (or do you not) obtain the same solution as your earlier one?</span>
        
             
        
        
        
Get a C once every two quarters and you’ll pass my guy
        
                    
             
        
        
        
The first two were negative integers and the quotient is therefor a positive integer (Two negatives equal a positive)
        
             
        
        
        
X=-5 and y=1
you would replace the letter x or y with zero to find the intercept.