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Alexeev081 [22]
3 years ago
5

Ahmed spent 2/3 of his money on a burrito and a water. The burrito coast 2 times as much as the water. The burrito cost $4, how

much money does Ahmed have left?
Mathematics
2 answers:
Lady_Fox [76]3 years ago
5 0
The burrito costs twice as much as water. Let's assume the water costs $w
$4=2w
w=$2 
Ahmed spent $2+$4=$6
2/3 of the total amount = $6
Total amount =$6x3/2
                      =$9
JulsSmile [24]3 years ago
4 0
If a burritto is twice as much as water the the water is two dollars. if Ahmed spent 2/3 of his money then( 4+2=6) for burrito and water it means he had nine dollars originally so he is left with 3 dollars.  <span />
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b) P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

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Assuming the following table:

                                                     Purchased Gum      Kept the Money   Total

Students Given 4 Quarters              25                              14                      39

Students Given $1 Bill                       15                               29                    44

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a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

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B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}

And if we replace we got:

P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

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B= "student was given $1 Bill"

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For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}

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c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

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3 years ago
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