Answer:
Step-by-step explanation:
1. Null hypothesis: u <= 0.784
Alternative hypothesis: u > 0.784
2. Find the test statistics: z using the one sample proportion test. First we have to find the standard deviation
Using the formula
sd = √[{P (1-P)}/n]
Where P = 0.84 and n = 750
sd =√[{0.84( 1- 0.84)/750]}
sd=√(0.84 (0.16) /750)
SD =√(0.1344/750)
sd = √0.0001792
sd = 0.013
Then using this we can find z
z = (p - P) / sd
z = (0.84-0.784) / 0.013
z =(0.056/0.013)
z = 4.3077
3. Find the p value and use it to make conclusions...
The p value at 0.02 level of significance for a one tailed test with 4.3077 as z score and using a p value calculator is 0.000008254.
4. Conclusions: the results is significant at 0.02 level of significance suck that we can conclude that its on-time arrival rate is now higher than 78.4%.
(5+1+1)*2 + 5*5*5*(1+5)*4 = 3014
Rooms = 5*5 = 25
Cats per room = 5 + 5*5 = 30
All cats legs = 25*30*4 = 3000
All humans = 1+1+5 = 7
All humans legs = 7*2 = 14
All legs = 3000 + 14 = 3014
Answer:
Step-by-step explanation:
Rate = 56 gal / 7 min
= 8 gal / min
For every 77 followers briana has 11 followers
