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3 years ago

14

Frank has a circular garden. The area of the garden is 100 ft2. What is the approximate distance from the edge of Frank’s garden

to the center of the garden? (A = πr2)

1 answer:

Arisa [49]3 years ago

5 0

100 = (22/7 )* r ^2
or r^ 2 = (100*7)/22
or r = 5.64 ft

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Answer:

Equation have Unique solution i.e $x=-20$

Step-by-step explanation:

Given Equation:

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3 years ago

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Read 2 more answers

The population of rabbits on an island is growing exponentially. In the year 1994, the population of rabbits was 9600, and by 20

drek231 [11]

Answer:

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Step-by-step explanation:

Given that the population of rabbits on an island is growing exponentially.

Let the population, $P=P_0e^{bt}$

where, $P_0$ and b are constants, t=(Current year -1994) is the time in years from 1994.

In 1994, t=0, the population of rabbit, P=9600, so

$9600=P_0e^{b\times 0}$

So, $P_0=9600$

and in 2000, t=2000-1994=6 years and population of the rabbit, P=18400

$18400=9600 \times e^{b\times 6} \\\\\frac{18400}{9600}=e^{b\times 6} \\\\$

$\ln(23/12}=6b \\\\$

$b = \frac{\ln{1.92}}{6} \\\\$

b=0.109

On putting the value of P_0 and b, the population of the rabbit after t years from 1994 is

$P=9600 \times e^{0.109\times t}$

In 2009, t= 2009-1994=15 years,

So, the population of the rabbit in 2009

$P=9600 \times e^{0.109\times 15}=49243$

Hence, the population of the rabbit in 2009 is 49243.

7 0

3 years ago