Answer:
The length of the other leg of this right angled triangle is 30 inches.
Step-by-step explanation:
We are given the following in the question:
A right angles triangle with the hypotenuse of 34 inches and the length of one of its legs is 16 inches.
Pythagoras theorem:
- The sum of of square of two sides of a triangle is equal to the square of the hypotenuse.
Let x inches be the length of the other leg of this right triangle.
Thus, we can write the equation:

Thus, the length of the other leg of this right angled triangle is 30 inches.
12 is the answer
6(7-5)
42-30
12
Set them equal to each other and solve
3x + 39 = 4x +34
-x=-5
X=5
Plug it in
3(5) + 39 = 54
4(5) +34 = 54
For the final angle ,
54 + 54 = 108
180-108 =72
The angle measures are 54,54, and 72
Answer:
The only point (0,0) lies inside the shaded region and hence it gives a solution for the set of inequalities.
Step-by-step explanation:
See the graph attached to this question.
The solution of the set of inequalities is given by the shaded region on the graph.
Now, the point (0,5) is outside this shaded region, hence it can not be the solution.
The point (3,0) also is outside this shaded region, hence it can not be the solution.
The point (-3,0) also is outside this shaded region, hence it can not be the solution.
Now, the only point (0,0) lies inside the shaded region and hence it gives a solution for the set of inequalities. (Answer)
Answer:
By exterior angle theorem, we have;
∠DBE = ∠H + ∠HEB = ∠ECD = ∠H + ∠HDC
∴ ∠H + ∠HEB = ∠H + ∠HDC
By addition property of equality, we have
∠HEB = ∠HDC
∠H = ∠H by reflexive property
∴ ΔHCD ~ ΔHEB by Angle Angle AA similarity postulate
∴ HE/HD = EB/DC, by the definition of similarity
Therefore, by cross multiplication, we have;
HE × DC = EB × HD
Therefore, by commutative property of multiplication, we have;
HE × DC = HD × EB
Step-by-step explanation: