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adelina 88 [10]
3 years ago
12

In circle K shown below, points B, C, D, and E lie on the circle with secants HBD and HCE drawn. Prove:

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0

Answer:

By exterior angle theorem, we have;

∠DBE = ∠H + ∠HEB = ∠ECD = ∠H + ∠HDC

∴ ∠H + ∠HEB = ∠H + ∠HDC

By addition property of equality, we have

∠HEB = ∠HDC

∠H = ∠H by reflexive property

∴ ΔHCD ~ ΔHEB by Angle Angle AA similarity postulate

∴ HE/HD = EB/DC, by the definition of similarity

Therefore, by cross multiplication, we have;

HE × DC = EB × HD

Therefore, by commutative property of multiplication, we have;

HE × DC = HD × EB

Step-by-step explanation:

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This is a very interesting question.  Draw a line from the origin to where the upper right vertex of the square touches the line. That line has the property that the its equation is y = x. So the "solution" to the point of intersection is the solution of the two equations.

y =  x            (1)

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Put x in for y in equation 2

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Problem A

<em><u>x intercept</u></em>

The x intercept occurs when y = 0

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x and y both equal 1.714 so they are also the length of the square's side.

Problem C

See solution above. x =y is the key fact.

x = y = 1.714

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Tony has 6 dollars in change in his car. Every time he drives to visit his grandma, he pays $1.25 in tolls. Which graph represen
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The slope of a line is undefined, and the x-intercept is -7. what is the equation of the line?​
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The equation of line with undefined slope and x - intercept -7 is x = -7

<em><u>Solution:</u></em>

Given that the slope of line is undefined and the x intercept is -7

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