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adelina 88 [10]
3 years ago
12

In circle K shown below, points B, C, D, and E lie on the circle with secants HBD and HCE drawn. Prove:

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0

Answer:

By exterior angle theorem, we have;

∠DBE = ∠H + ∠HEB = ∠ECD = ∠H + ∠HDC

∴ ∠H + ∠HEB = ∠H + ∠HDC

By addition property of equality, we have

∠HEB = ∠HDC

∠H = ∠H by reflexive property

∴ ΔHCD ~ ΔHEB by Angle Angle AA similarity postulate

∴ HE/HD = EB/DC, by the definition of similarity

Therefore, by cross multiplication, we have;

HE × DC = EB × HD

Therefore, by commutative property of multiplication, we have;

HE × DC = HD × EB

Step-by-step explanation:

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The cost of a shirt and a pair of pants is the same and is equal to $2. The correct option is B.

<h3>What is a solution to a system of equations?</h3>

For a solution to be the solution to a system, it must satisfy all the equations of that system, and as all points satisfying an equation are in their graphs, so solution to a system is the intersection of all its equation at a single point(as we need a common point, which is going to be the intersection of course)(this can be one or many, or sometimes none)

Let x represent the cost of a shirt, while y represent the cost of a pair of pants.

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Also, Mike bought 1 shirt and 1 pair of pants for $4. Therefore, the equation that represents this situation is,

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Learn more about finding the solution graphically here:

brainly.com/question/26254258

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