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3 years ago

In circle K shown below, points B, C, D, and E lie on the circle with secants HBD and HCE drawn. Prove:

Mathematics

1 answer:

Alexxx [7]3 years ago

3 0

Answer:

By exterior angle theorem, we have;

∠DBE = ∠H + ∠HEB = ∠ECD = ∠H + ∠HDC

∴ ∠H + ∠HEB = ∠H + ∠HDC

By addition property of equality, we have

∠HEB = ∠HDC

∠H = ∠H by reflexive property

∴ ΔHCD ~ ΔHEB by Angle Angle AA similarity postulate

∴ HE/HD = EB/DC, by the definition of similarity

Therefore, by cross multiplication, we have;

HE × DC = EB × HD

Therefore, by commutative property of multiplication, we have;

HE × DC = HD × EB

Step-by-step explanation:

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44 lb 6 oz = ____ ounces

hodyreva [135]

Answer:

710 oz

Step-by-step explanation:

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3 years ago

Harlan played her favorite game app three times this morning in each game the number of points she scored was a prime number whe

zavuch27 [327]

Can't help if I don't know what the question is

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4 years ago

What initial investment must be made to accumulate $60000 in 17 years if the money is invested in a mutual fund that pays 12% an

mars1129 [50]

$7881.18

Step-by-step explanation:

Let the initial Investment be $P_{0}$ . The Interest is compounded on a monthly basis at 12% annual interest rate. After 17 years, the Investment amounts to $60,000.

As the annual interest rate is 12%, the monthly interest rate is 1%.

Since this is a compound interest problem, the total amount can be modeled as follows: $P(t)=P_{0}(1+\frac{i}{100})^{t}$

Here $i$ is the interest rate, i.e $1$ , and t is the number of time periods, i.e $17\textrm{ years x }12\frac{\textrm{months}}{\textrm{year}}$ = $204\textrm{ months}$

$60,000=P_{0}\textrm{ x }(\frac{101}{100})^{204}$

$P_{0}=7881.18$

∴ Initial Investment = $7881.18

4 0

3 years ago

A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of

Eva8 [605]

Answer:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=250000$ represent the sample mean

$s=37500$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =210250$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:

Null hypothesis: $\mu \leq 210250$

Alternative hypothesis: $\mu > 210250$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

Conclusion

Since is a one right tailed test the p value would be:

$p_v =P(t_{4}>2.37)=0.038$

6 0

3 years ago

The discriminant for the equation f(x)=6x^(2)-x+c is 73. What is the value of c?

Andrews [41]

Answer:

c = -3

Step-by-step explanation:

The discriminant is 73, that means we have:

(-1)^2-4*6*c=73

then: 1-24c=73

or -24c= 73 -1

-24c = 72

Then c = 72/-24= -3

The answer is -3

Hope that useful for you.

5 0

3 years ago