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LenaWriter [7]
3 years ago
7

How to find the minimum value of f(x) = 3x (x - 4)?

Mathematics
1 answer:
DaniilM [7]3 years ago
4 0

well, let's first off, expand the expression, 3x(x-4) => 3x²-12x, which we can also write as

f(x) = 3x² - 12x + 0

now, this is a quadratic equation with a leading term with a positive coefficient, namely its graph is a parabola, or a Cup-Shaped figure, so the graph comes from the top, goes down down down, reaches a U-turn, then goes back up up up.

the U-turn, or vertex of the quadratic, is the lowest point in the "cup".


\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ \stackrel{f(x)}{y}=\stackrel{\stackrel{a}{\downarrow }}{3}x^2\stackrel{\stackrel{b}{\downarrow }}{-12}x\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{(-12)}{2(3)}~~,~~0-\cfrac{(-12)^2}{4(3)} \right)\implies \left( \cfrac{12}{6}~,~0-\cfrac{144}{12} \right)\implies (2~,~-12)

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AnnZ [28]
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3 years ago
PLEASE HELP I WILL GIVE BRAINLIEST
Likurg_2 [28]

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Step-by-step explanation:

7 0
3 years ago
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A rectangular box is designed to have a square base and an open top. The volume is to be 500in.3 What is the minimum surface are
mr_godi [17]

The minimum surface area that such a box can have is 380 square

<h3>How to determine the minimum surface area such a box can have?</h3>

Represent the base length with x and the bwith h.

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x^2h = 500

Make h the subject

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Expand

S = 2x^2 + 4xh

Substitute h = 500/x^2

S = 2x^2 + 4x * 500/x^2

Evaluate

S = 2x^2 + 2000/x

Differentiate

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Set the equation to 0

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Multiply through by x^2

4x^3 - 2000 = 0

This gives

4x^3= 2000

Divide by 4

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Take the cube root

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Substitute x = 7.94 in S = 2x^2 + 2000/x

S = 2 * 7.94^2 + 2000/7.94

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Hence, the minimum surface area that such a box can have is 380 square

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5 0
2 years ago
Solve <br><br> 9(a + 2b) + c <br><br> a = 3 <br> b = 2<br> c = 1
swat32

Answer:

64

Step-by-step explanation:

Step 1: Define

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b = 2

c = 1

Step 2: Substitute and Evaluate

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9(3 + 4) + 1

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63 + 1

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