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3 years ago

14

Evaluate (-A) 2 for A = 5, B = -4, and C= 2. 0-25 -10 10 25

1 answer:

Alenkinab [10]3 years ago

4 0

Answer:

-10

Step-by-step explanation:

Substitute 5 into the equation

(-5)2

Simplify and get -10

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A bag contains 8 blue marbles, 6 green marbles, 12 yellow marbles, and 10 orange marbles. A marble is drawn at random from the b

VladimirAG [237]

Total Marbles = 8 + 6 + 12 + 10 = 36

Probability the marble is blue = 8/36

Inverse this to get the probability of the marble not being blue

Probability of the marble not being blue = 28/36 = 7/9

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3 years ago

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The time between arrivals of taxis at a busy intersection is exponentially distributed with a mean of 10 minutes. (a) What is th

Sindrei [870]

Answer:

a) 0.0025

b) 0.9975

c) 23.03 minutes

d) 23.03 minutes

Step-by-step explanation:

Let X be the random variable that measures the time waited for a taxi.

If X is exponentially distributed with a mean of 10 minutes,then the probability that you have to wait more than t minutes is

$\large P(X>t) = e^{-t/10}$

a)

1 hour = 60 minutes, so the probability that you wait longer than one hour is

$\large P(X>60)=e^{-6}=0.0025$

b)

Due to the “memorylessness” of the exponential distribution, the probability that you have to wait 10 or less minutes after you have already waited for one hour, is the same as the probability that you have to wait 10 or less minutes

$\large P(X\leq 10)=1-e^{-6}=0.9975$

c)

We want x so that

P(X>x)=0.1

$\large e^{-x/10}=0.1\rightarrow -x/10=ln(0.1)\rightarrow x=-10ln(0.1)=23.03\;minutes$

d)

We want P(X<x)=0.9

$\large 1-e^{-x/10}=0.9\rightarrow e^{-x/10}=0.1\rightarrow x=-10ln(0.1)=23.03\;minutes$

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3 years ago

What makes headlines? (Geojoke answer) (this is for trigonometric ratios)

Fudgin [204]

Answer:

sorry what do you mean

Step-by-step explanation:

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2 years ago

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4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

as

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

so

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

so

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

so

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

so

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

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3 years ago

there are some cows and some chickens, if there are a total of 40 heads and 112 legs, how many cows are there

Dominik [7]

ummm I think I know but I don't at the same time take away 40 from 112 and theres you answer♥.

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2 years ago

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