There were 6 students running in a race. How many different arrangements of first, second, and third place are possible?
1 answer:
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The completely factored equation is (a²b - 5)(4a²b - 1)
<h3>How to factor equation?</h3>4a⁴b² - 21a²b + 5 = 0
let's expand the equation
Therefore,
4a⁴b² - 21a²b + 5 = 0
4a⁴b² - 20a²b - a²b + 5 = 0
Rearrange the equation
4a⁴b² - a²b - 20a²b + 5 = 0
Let's factorise the equation
4a⁴b² - a²b - 20a²b + 5 = 0
a²b(4a²b - 1) - 5(4a²b - 1) = 0
Therefore, the completely factored equation is as follows:
a²b(4a²b - 1) - 5(4a²b - 1) = 0
(a²b - 5)(4a²b - 1)
learn more on equation here: brainly.com/question/8842252
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