Answer:
x=-6
Step-by-step explanation:
use distributive property on the () and times x and 1 by three
then you subtract 6 from both sides
then subtract three from both sides
then divide both sides by 3
your work would look like this:
3(x+1)+6=-9
3x+3+6=-9
3x+3=-15
3x=-18
x=-6
Hope this helps!
65:100 because there are 65 girls and then 65 girls + 35 boys = 100 total students
We know how wide the billboard will be. Therefore, to know how much the original image should be enlarged, you must divide the final width of the billboard between the current width of the invoice.
We know both data, then we perform the operation:
48 feet /6.14 inches = 7.81 feet / inches
.
Therefore the correct answer is option D. 1″ = 7.81′
For the bill to cover the billboard, the bill must be expanded by a factor of 7.81 feet long per inch long that has the original image.
Answer:
Step-by-step explanation:
We'll take this step by step. The equation is
![8-3\sqrt[5]{x^3}=-7](https://tex.z-dn.net/?f=8-3%5Csqrt%5B5%5D%7Bx%5E3%7D%3D-7)
Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:
![-3\sqrt[5]{x^3}=-15](https://tex.z-dn.net/?f=-3%5Csqrt%5B5%5D%7Bx%5E3%7D%3D-15)
The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:
![\sqrt[5]{x^3}=5](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E3%7D%3D5)
Let's rewrite that radical into exponential form:

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:
![x=\sqrt[3]{5^5}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%5E5%7D)
Let's group that radicad into groups of 3's now to make the simplifying easier:
because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:
which is the same as:
![x=5\sqrt[3]{25}](https://tex.z-dn.net/?f=x%3D5%5Csqrt%5B3%5D%7B25%7D)
Answer:
1. A sound wave in air has a frequency of 262 Hz and travels at a speed of 330 m/s.
2. Sound has a speed of 340 m/s in air at room temperature.
3. A wave has a frequency of 500 Hz and a wavelength of
4. The speed of light is 3.0x10^8 m/s, calculate for the frequency.
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