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Monica [59]
3 years ago
13

Ascatterplot has a negative, linear correlation. Which statement is true about the relationship between the x- and y-values?

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0

Answer:

B) As the x-values increase, the y-values tend to decrease

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Racionalize o denominador da equação abaixo:<br> 5 + 3 ²√5 / ²√5
GrogVix [38]
I hope this helps

\cfrac{5+3 \sqrt{5} }{ \sqrt{5} } =\cfrac{(5+3 \sqrt{5}) \sqrt{5}  }{ \sqrt{5}* \sqrt{5}  }= \cfrac{5 \sqrt{5}+15 }{5}  = \cfrac{5 (\sqrt{5}+3) }{5}  = \sqrt{5}+3
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3 years ago
On Friday,65% of the students at Plainview Middle School bought a hot lunch and the rest of the students packed their lunch. Wha
oksano4ka [1.4K]
35% packed their lunch. 65/100 bought hot lunch. 100-65=35. 
7 0
3 years ago
Solve 4x2−10x−6=0 using the Quadratic Formula.
vazorg [7]

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x=−1

x=−1.5

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5 0
2 years ago
(adapted from Ross, 2.31) Three countries (the Land of Fire, the Land of Wind, and the Land of Earth) each make a 3 person team.
DaniilM [7]

Answer:

The answer is "\frac{2}{9} \  and \ \frac{1}{9}"

Step-by-step explanation:

In point a:

The requires  1 genin, 1 chunin , and 1 jonin to shape a complete team but we all recognize that each nation's team is comprised of 1 genin, 1 chunin, and 1 jonin.

They can now pick 1 genin from a certain matter of national with the value:

\frac{1}{\binom{3}{1}}=\frac{1}{3} .

They can pick 1 Chunin form of the matter of national with the value:

\frac{1}{\binom{3}{1}}=\frac{1}{3} .

They have the option to pick 1 join from of the country team with such a probability: \frac{1}{\binom{3}{1}}=\frac{1}{3}

And we can make the country teams: 3! = 6 different forms. Its chances of choosing a team full in the process described also are:

6 \times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{2}{9}.

In point b:

In this scenario, one of the 3 professional sides can either choose 3 genins or 3 chunines or 3 joniners. So, that we can form three groups that contain the same ninjas (either 3 genin or 3 chunin or 3 jonin).

Its likelihood that even a specific nation team ninja would be chosen is now: \frac{1}{\binom{3}{1}}=\frac{1}{3}

Its odds of choosing the same rank ninja in such a different country team are: \frac{1}{\binom{3}{1}}=\frac{1}{3}

The likelihood of choosing the same level Ninja from the residual matter of national is: \frac{1}{\binom{3}{1}}=\frac{1}{3} Therefore, all 3 selected ninjas are likely the same grade: 3\times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{1}{9}

4 0
3 years ago
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How do you write .049 in expanded form?
IgorC [24]
0.049=0.04+0.009
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3 years ago
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