Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
Answer:
-25
Step-by-step explanation:
2a² - 5a + 4, for f(-3)
2(-3)² -5(-3)+4
2*(-27)+15+4
-54+19
= -25
The best answer is 15/8 and it could be simplified I think
Answer:
Molly's Z score for LSAT
z-score=-2
Molly's Z score for MCAT
z-score=2
Step-by-step explanation:
z-score for LSAT
Molly's score=120
mean=150
Standard deviation=15
z-score= (Molly LSAT score-mean)/standard deviation
z=120-150/15=-30/15=-2
z-score for MCAT
Molly's score=52
mean=40
Standard deviation=6
z-score= (Molly MCAT score-mean)/standard deviation
z=52-40/6=12/6=2
Answer:
3
Step-by-step explanation:
Because there is only one table and you are asking for only one answer
