The answer will be similar as 7x20=140 and 7x2000=14000, the answers are the same but x100 as 140x100=14000
20x100=2000
Answer:
6
/19
≅ 0.3157895
Step-by-step explanation:
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
#SPJ1
Answer:
D. 6
Step-by-step explanation:
the similarity theorem:
x/9 = 8/12
12x=8 (9)
12x = 72
x = 72/12
x = 6
Answer:
Step-by-step explanation:
To evaluate for such, the following comprehension is required,
Equation Required: Distance Formula: d(P, Q) = √ (x2 − x1)^2 + (y2 − y1)^2
Denote the configurations as the following,
(5, -1). (5, -4)
X1 Y1. X2. Y2
D(P, Q) = √(5 - 5)^2 + (-4 +1)^2. <== Since the double negative is present, the operation is acknowledged as positive.
D(P, Q) = √(0)^2 + (-3)^2
D(P, Q) = √9 = 3
Thus, the agglomerate distance between the points situated in the Cartesian plane is disclosed, and is, henceforth, disseminated as 03 units.
