Every female chicken lays 4 eggs. What is the constant of proportionality for the ratio of eggs to female chickens? 4 3

1 answer:

4 0

Since every female chicken lays 4 eggs, if you have one chicken you have 4 eggs, if you have two chicken you have 8 eggs, and so on.

We can even build a little table to show some values:

$\begin{array}{c|c}1&4\\2&8\\3&12\\4&16\\5&20\\\vdots & \vdots\\n& 4n\end{array}$

So, as you can see, the ratio between the number of eggs and the number of female chicken is 4.

You might be interested in

The price of an item has been reduced by <br> 45% <br> . The original price was <br> $17

Artist 52 [7]

Price is reduced by 45%. Which means that the new price is 55% of the original.
Therefore, (55/100)*17 = $9.35 =new price

8 0

3 years ago

Evaluate the expression below at x=5

Citrus2011 [14]

5 is the answer to the promblem

5 0

2 years ago

There are 49 counters in a bag.

emmainna [20.7K]

Answer:

Explanation:

49-20=29 blue counters

There’s a 29/49 chance that the counter will be blue

4 0

2 years ago

There are currently 17 frogs in a (large) pond. The frog population grows exponentially, tripling every 6 days. How long will it

Tema [17]

Answer:

t=11,11 days

Step-by-step explanation:

F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating $\int\limits^ {} \, dF/F =K\int\limits^ {} \, dt$ ⇒ LnF=Kt+c, $F=ce^{Kt}$ ; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)), $F=ce^{K0} = F=c=17; F=17e^{6K} =51$ ⇒ $e^{6K} =51/17; K6=ln\frac{51}{17} ; K=ln\frac{51}{17}/6=0.183$ , so $F=17e^{0,183t}$ , now if F=130, t=? we have: