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miskamm [114]
3 years ago
13

Estimate product 885 x 3

Mathematics
1 answer:
solniwko [45]3 years ago
7 0
<span>2655

hope this helps. c:</span>
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The solution to (d+4)^2=9 is D=
Allushta [10]

Answer:

\boxed{\sf d = -1 \ \ \ or \ \ \ d = -7}

Step-by-step explanation:

\sf Solve \:  for  \: d  \: over  \: the  \: real  \: numbers: \\  \sf \implies {(d + 4)}^{2}  = 9 \\  \\  \sf Take  \: the \:  square  \: root \:  of  \: both \:  sides: \\  \sf \implies \sqrt{ {(d + 4)}^{2} }  =  \sqrt{9}  \\  \\  \sf 9 =  {3}^{2} :   \\  \sf \implies \sqrt{ {(d + 4)}^{2} }  =  \sqrt{ {(3)}^{2} }  \\  \\  \sf \implies d + 4 =  \pm 3 \\  \\  \sf \implies d + 4 = 3 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: d + 4 =  - 3 \\  \\  \sf Subtract  \: 4  \: from \:  both \:  sides:   \\ \sf \implies d + (4  - 4)= 3 - 4 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: d + (4 - 4) =   - 3  - 4  \\  \\ \sf \implies d =  - 1 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: d  =  - 7

4 0
3 years ago
Read 2 more answers
The product of two consecutive room numbers is 342. Find the room numbers.
Paraphin [41]
To determine this easily, figure out what two numbers will make a product ending with "2", (4 & 3, 8 & 9)
Since the square root of 625 is 25, it is obviously less than 25.
I used 18 and 19, and they are the correct answer.
6 0
3 years ago
Write 6324 correct to the nearest thousand?
dalvyx [7]

Answer:

6000

6 is in the thousands place, since 3 is less than five, you round down.

4 0
3 years ago
Read 2 more answers
Round up 15.23 to the nearest tenth
rewona [7]
Round up 15.23 to the nearest tenth.

15.23

Look after the tenth place which is 3. Is this number number before or after 5? Yes! Its before, so we round back which would make 15.23 to the nearest tenth is 15.20. 

15.23 rounded to the nearest tenth = 15.20. 
3 0
4 years ago
Read 2 more answers
Work out an expression for the nth term for this sequence:<br><br> 23,35,47,49
notsponge [240]
<h3>Answer:</h3>

a_n = 23 +12(n -1)

<h3>Explanation:</h3>

The nth term of an arithmetic sequence is explicitly defined as a_n = a_1 +d(n -1) where a_1 is the first term of the sequence and d is the the common difference.

From the given first five terms of the sequence we can see that the first term is 23 so a_1 = 23.

The common difference, d, can be calculated by a_n - a_{n -1} so we'll find the common difference of the given sequence by letting n = 2

d = a_2 - a_{2 -1} \\d = a_2 -a_{1} \\d = 35 -23 \\ d = 12.

Now let's plug everything we know.

a_1 = 23

d = 12

a_n = 23 + 12(n -1)

7 0
3 years ago
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