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liq [111]
4 years ago
11

What is the answer 5x-3 =1/5x

Mathematics
1 answer:
Oxana [17]4 years ago
3 0

Answer:

x = 5/8 for 5x - 3 = (1/5)x

Step-by-step explanation:

To find x, we want to isolate our 3 from our x-values. You can add three to both sides of the equation and get it to the other side and then subtract 1/5x from 5x.

(5x - 3) + 3 = ((1/5)x) + 3

5x = (1/5)x + 3

5x = (25/5)x

((25/5)x) - (1/5)x = ((1/5)x + 3) - (1/5)x

(24/5)x = 3

From here, you would want to solve for x. This would mean multiplying 3 by 5 and dividing your product by 24.

5*3 = 15

15/24 = 5/8 = x

Hope this helps!

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You earn $0.85 for every cup of hot chocolate you sell. Write and solve an equation to determine how many cups you need to sell
antoniya [11.8K]

Answer:

47 rounding to nearest 100th

Step-by-step explanation:

Divide 55.25 into 0.85 and get 46.96 then round to get 47 cups.

6 0
3 years ago
What is the best approximation of the length of segment QS? (Note: cos 80° = 0.17)
matrenka [14]

Answer: QS=11.8cm


Step-by-step explanation:

1. You have the following information:

- The lenght of RS is 2 centimeters.

- The angle m∠S=80°.

- Cos80°=0.17

2. Therefore, you can calculate the lenght of the segment QS as following:

cos80=\frac{adjacent}{hypotenuse}

adjacent=2cm\\hypotenuse=QS\\cos80=0.17

3. Substitute values and solve for QS:

0.17=\frac{2cm}{QS}\\QS=\frac{2cm}{0.17} \\QS=11.76cm

4. To the nearest tenth:

QS=11.8cm

6 0
4 years ago
Yoshi's garden three fourths of the flowers are tulips of the two thirds are yellow what fraction of the flowers in Yosi's garde
Alex_Xolod [135]
So if yosh has a garden with 3/4 of the flowers are tulips and 2/3 are yellow if you subtract 3/4 from 2/3 then you will get the awnser that you are looking for. Which is 1/12.
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4 years ago
What is the y- intercept of a line that has a slope of -3 and passes through point (-5,4)?​
OlgaM077 [116]

Answer:B is the answer -11

Step-by-step explanation:

3 0
3 years ago
Find the distance between A(2,4) B(3,6)
Irina-Kira [14]

Answer:

d = \sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point A (2, 4)

Point B (3, 6)

<u>Step 2: Find distance </u><em><u>d</u></em>

  1. Substitute:                    d = \sqrt{(3-2)^2+(6-4)^2}
  2. Subtract:                       d = \sqrt{(1)^2+(2)^2}
  3. Exponents:                   d = \sqrt{1+4}
  4. Add:                              d = \sqrt{5}
5 0
3 years ago
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