1 2/5 BOOM mathed 4 dayz ~ vinny
<span> by taking integral we get
integral sec(x) (tan(x)+sec(x)) dx
applying integral we get
sec(x) (tan(x)+sec(x)) gives sec^2(x)+tan(x) sec(x)
= integral (sec^2(x)+tan(x) sec(x)) dx
Integrate the sum term by term
= integral sec^2(x) dx+ integral tan(x) sec(x) dx
For the integrand tan(x) sec(x), now we will use substitution
substitute u = sec(x) and du = tan(x) sec(x) dx
= integral 1 du+ integral sec^2(x) dx
The integral of sec^2(x) is tan(x)
= integral 1 du+tan(x)
The integral of 1 is u
= u+tan(x)+constant
Substitute the value of u which is equal to
= sec(x):
so our conclusion is
:tan(x)+sec(x)+constant
hope this helps</span>
Answer:
V = one-third pi (4 squared) (7) feet cubed
Step-by-step explanation:
Volume of cone v = 1/3×π(r²h)
r = 4 and h = 7
V = 1/3 × π(4²×7)
Since ABC is a right triangle, we can use Pythagorean Theorem to solve for side AB.
Pythagorean Theorem: a^2 + b^2 = c^2
4^2 + 7^2 = c^2
16 + 49 = c^2
65 = c^2
c = 8.06
Hope this helps!! :)
Well i atleast know its not 10 lol