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2 years ago

What is the difference of the rational expressions below?

Mathematics

1 answer:

Rom4ik [11]2 years ago

3 0

Answer:

** +2x

Step-by-step explanation:

All the other ones can be it any thing will have difference but how can you do it?

* -sign mutipulcation

2x+* can be different.

O c, OA is N X+2 and more is not a equation. * - can be times really any number.

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Solve, 6 (5x -2) + 12 = 30

jeyben [28]

Step-by-step explanation

6 (5x -2) + 12 = 30

30x-12+12=30

30x=30

x=30/30

x=1

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2 years ago

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3 years ago

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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

Viefleur [7K]

Answer:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

$n = 1537, \pi = \frac{353}{1537} = 0.2297$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 - 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2087$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 + 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2507$

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

7 0

3 years ago

I don’t know the answer or how to do this, help!

makvit [3.9K]

Answer:

Step-by-step explanation:

y = x^2 - x - 12

y = (x-4)×(x+3) that means x it either 4 or -3

y = x + 3

for x = 4 ➡ y = 3+4 ➡7

for x = -3 ➡ y = -3 + 3➡0

(the answer key is most probably faulty there's no way for y to be 0 in both scenarios)

6 0

2 years ago