Question

Multiply Conjugates Using the Product of Conjugates Pattern

Answer 1

Answer:

The product is the difference of squares is $(9c-2d)(9c+2d)=81{{c}^2}-4{{d}^2}$

Step-by-step explanation:

Explanation

• The given expression is (9c-2d)(9c+2d).

• We have to multiply the given expression.

• Square the first term 9c. Square the last term 2d.

$\begin{aligned}&(9 c-2 d)(9 c+2 d)=(9 c)^{2}-(2 d)^{2} \\&(9 c-2 d)(9 c+2 d)=81 c^{2}-4 d^{2}\end{aligned}$