The pitch of sound is related to the ___ of the sound waves

Physics

2 answers:

tiny-mole [99]3 years ago

7 0

The pitch of sound is related to the frequency of the sound waves.

<u>Explanation: </u>

The sound waves are simply the vibrations of the particles in the medium. When these waves travel through the medium, the medium particles start vibrating. Now, these vibrations can hear by us when it hits our ear drums.

We hear sound of differently because of the level of vibrations of medium particles and the distance travelled by these vibrations to our ear drums. Now, there comes the frequency of sound waves. The frequency of sound waves defined as number of vibrations a medium particle performs in a unit time.

The sensation of frequency is referred as pitch of the sound wave. A high pitch sound means a sound wave of high frequency, whereas a lower pitch of sound corresponds to the low frequency of sound waves because of which the medium particles vibrates.

solniwko [45]3 years ago

4 0

Answer:

The answer is frequency - I think....sorry if I'm wrong.

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Which of the following expressions gives the ratio of the energy density of the magnetic field to that of the electric field jus

miss Akunina [59]

Answer:

$(d) \ \ \frac{\mu_o}{\epsilon_o} (\frac{L}{2\pi r*R} )^2$

Explanation:

Energy density in magnetic field is given as;

$U_B = \frac{1}{2 \mu_o} B^2$

where;

B is the magnetic field strength

Energy density of electric field

$U_E = \frac{1}{2}\epsilon E^2$

where;

E is electric field strength

Take the ratio of the two fields energy density

$\frac{U_B}{U_E} = \frac{1}{2\mu_o} B^2 / \frac{1}{2}\epsilon E^2\\\\\frac{U_B}{U_E} = \frac{B^2}{2\mu_o} *\frac{2}{\epsilon E^2} \\\\\frac{U_B}{U_E} = \frac{1}{\mu_o \epsilon} (\frac{B^2}{E^2})$