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julia-pushkina [17]
3 years ago
5

What characterizes static stretching? A. having a partner hold limbs in a stretch position B. assuming and holding a stretch pos

ition C. bouncing while in a stretch position D. using a tool or object to increase a stretch Please select the best answer from the choices provided. A B C D
Physics
2 answers:
balandron [24]3 years ago
7 0

Answer:

It is B

Trust me it is B

Neko [114]3 years ago
3 0

Answer:

B.

assuming and holding a stretch position

Explanation:

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A mass of 5.00 kg pulls down vertically on a string that is wound around a rod of radius 0.100 m and negligible moment of inerti
fiasKO [112]

Answer:

<em>0.981 rad/sec^2</em>

<em></em>

Explanation:

mass that pulls on string = 5 kg

weight due to mass = 5 x 9.81 = 49.05 N

radius of rod = 0.1 m

torque produced by this force on the rod = force x radius

torque = 49.05 x 0.1 = 4.905 N-m

mass of disk = 125 kg

radius of disk = 0.2 m

moment of inertia of the disk I = mr^{2}

I = 125 x 0.2^{2} = 5 kg-m^2

from the equation, <em>T = Iα</em>

where T is torque

I is moment of inertia

α is angular acceleration

imputing values,

4.905 = 5α

α = 4.905/5 = <em>0.981 rad/sec^2</em>

5 0
3 years ago
A series RL circuit with L = 3.00 H and a series RC circuit with C = 3.00 F have equal time constants. If the two circuits conta
Tems11 [23]

Answer:

(a) R = 1Ω

(b) τ = 3

Explanation:

The time constants of the given circuits are as follows

\tau_{RL} = \frac{L}{R}\\\tau_{RC} = RC

If the two circuits have equal time constants, then

\frac{L}{R} = RC\\R^2 = \frac{L}{C} = \frac{3}{3} = 1\\R = 1\Omega

Therefore, the time constant in any of the circuits is

\tau = RC = 3

6 0
3 years ago
A 33.0-kg child starting from rest slides down a water slide with a vertical height of 15.0 m. (Neglect friction.)
Temka [501]

This question involves the concept of the conservation of energy.

(a) The child's speed halfway will be "12.13 m/s".

(b) The child's speed three-fourth way will be "14.86 m/s".

(a)

Using the <em>law of conservation of energy</em>:

Potential Energy Lost = Kinetic Energy Gained

mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\v = \sqrt{2gh}

where,

v = speed = ?

g = acceleration due to gravity = 9.81 m/s²

h = height lost = halfway = height/2 = 15 m/2 = 7.5 m

Therefore,

v = \sqrt{(2)(9.81\ m/s^2)(7.5\ m)}

<u>v = 12.13 m/s</u>

<u />

(b)

Using the <em>law of conservation of energy</em>:

Potential Energy Lost = Kinetic Energy Gained

mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\v = \sqrt{2gh}

where,

v = speed = ?

g = acceleration due to gravity = 9.81 m/s²

h = height lost = three-fourth way down = \frac{3}{4}height = \frac{3}{4}(15\ m) = 11.25\ m

Therefore,

v = \sqrt{(2)(9.81\ m/s^2)(11.25\ m)}

<u>v = 14.86 m/s</u>

<u />

Learn more about the <em>law of conservation</em> of energy here:

brainly.com/question/20971995?referrer=searchResults

The attached picture shows the <em>law of conservation of energy</em>.

7 0
3 years ago
10^-1 phones in microphones
Arada [10]
1 microphone = (presumably)  10⁻⁶ phone

1 phone = (presumably)  10⁶  microphones

(10⁻¹) phone  =  (presumably)  (10⁻¹) x (10⁶ microphones)

                       =       10⁵ microphones.
4 0
3 years ago
If two organisms evolve in response to each other, which evolutionary pattern is demonstrated
Taya2010 [7]
Something super duper uper stuper luper nuper tuper zuper yuper fuper guper huper kuper juper wuper special
6 0
3 years ago
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