From the table we can conclude that after 2 minutes the height of the water is increased by 4.
Example: In minute 2 it was 8 inches, in minute 4 it was 12 inches. (12-8=4)
This means that if the height of the water is increased by 4 inches for 2 minutes, then for 1 minute is increased 4/2=2 inches.
The following s<span>tatement best describes how the slope relates to the height of the water in the pool:
</span><span>The height of the water increases 2 inches per minute.</span>
Answer:
c=12
Step-by-step explanation:
12c - 53= 91
12c=144
c=12
Answer:
C. y +3 = x +3
Step-by-step explanation:
We need to find in below option x has direct variation with y.
We solve for each;
A. 
From above equation we can state that 2 times y is equal to 7 less than 3 times of x.
Hence it doesn't represent direct variation.
B. 
Solving above expression we get;
From above equation we can state that y is equal to 10 more than x.
Hence it doesn't represent direct variation.
C. 
Solving above expression we get;
From above equation we can state that y is equal to x.
Hence it represent direct variation.
D. 
Solving above expression we get;
From above equation we can state that 4 times y is equal to 2 less than 4 times of x.
Hence it doesn't represent direct variation.
Hence the Answer which represent direct variation of x and y is,
C.
For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
