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Verdich [7]
3 years ago
8

Round to the place value 286,476

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
8 0
257000  000000000000000000000000000000000000000000000000000000000000000000000000000000000
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Solve ax + b = cx + d for x.
romanna [79]

Answer: X = (d-b) / (a-c)

This way this worded is weird but I think I got it

Step-by-step explanation:

Subtract B from both sides

ax = cx +d -b

Then subtract CX from both sides

ax -cx =d-b

Distributive Property

x(a-c) =d-b

Divide both sides by a-c

X = (d-b) / (a-c)

6 0
2 years ago
Find the area of the shaded part in the given diagram
enyata [817]

Answer:

30cm^2

Step-by-step explanation:

area of large rectangle = length x width

= 5 X 9 = 45 cm^2

area of small rectangle = length x width

= 3 X 5 = 15 cm ^2

45 - 15 = 30cm^2

5 0
2 years ago
Can anyone help? Thank you.
Tcecarenko [31]

Answer:

  91.8 ft

Step-by-step explanation:

So we can talk about the diagram, let's name a couple of points. The base of the tree is point T, and the top of the tree is point H. We want to find the length of TH given the length AB and the angles HAT and ABT.

The tangent function is useful here. By its definition, we know that ...

  TA/BA = tan(∠ABT)

and

  TH/TA = tan(∠HAT)

Then we can solve for TH by substituting for TA. From the first equation, ...

  TA = BA·tan(∠ABT)

From the second equation, ...

  TH = TA·tan(∠HAT) = (BA·tan(∠ABT))·tan(∠HAT)

Filling in the values, we get ...

  TH = (24.8 ft)tan(87.3°)tan(9.9°) ≈ 91.8 ft

The height <em>h</em> of the tree is about 91.8 ft.

6 0
3 years ago
Ramona completed all 30 questions on the test. If 5/6 of the questions were correct, how many questions
Nitella [24]

Answer:

r

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Assume that military aircraft use ejection seats designed for men weighing between 141.8 lb and 218 lb. If​ women's weights are
Mariulka [41]

Answer:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(173.6,49.8)  

Where \mu=173.6 and \sigma=49.8

We are interested on this probability

P(141.8

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

8 0
3 years ago
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