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Reika [66]
3 years ago
12

Please help need 1 more to passss guys !!!!!!!!!!!!!

Mathematics
1 answer:
Drupady [299]3 years ago
7 0
A) 40
b) 3
c) 5

Hope this helps
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I need help with these 2 questions
tensa zangetsu [6.8K]
Number 1 would the last option, but I’m not sure about number 2
7 0
3 years ago
The coordinates of S are (5,4). What are the coordinates of S' after the figure is rotated 90 degrees about the origin? A.)?(-5,
Murrr4er [49]
The general rule for 90° counterclockwise rotation about the origin is given by:
(x,y)→(-y,x)
thus given that S has coordinates of (5,4), then rotation through 90° will map the the figure on S'(-4,5). Hence the answer is:
C](-4,5)
6 0
3 years ago
Carly grew 12 flowers with 3 seed packets. How many seed packets does Carly need to have a total of 20 flowers in her garden?
shepuryov [24]

Answer:

4 packs

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
From the given angle measurements, you can’t directly find the measure of angle L. However, you can find the measurement of angl
DaniilM [7]

The measurement of angle L = 50°.

Solution:

The given image is a rectangle.

The measurement of ∠A = 25°

The measurement of ∠B = 25°

ABC is a triangle.

Sum of the interior angles of the triangle = 180°

⇒ m∠A + m∠B + m∠C = 180°

⇒ 25° + 25° + m∠C = 180°

⇒ 50° + m∠C = 180°

⇒ m∠C = 180° – 50°

⇒ m∠C = 130°

Sum of the adjacent angles in a straight line = 180°

⇒ m∠C + m∠L = 180°

⇒ 130°  + m∠L = 180°

⇒ m∠L = 180° – 130°

⇒ m∠L = 50°

Hence the measurement of angle L = 50°.

8 0
3 years ago
Read 2 more answers
Anyone help me. ....​
weeeeeb [17]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

All the exponents inside the parenthesis are multiplied by the exponent outside the parenthesis.

Then

\frac{m^{-7}n^{14}  }{m^{-25}n^{40}  } ÷ \frac{m^{-21}n^{42}  }{m^{-25}n^{40}  }

[ Using the rule \frac{a^{m} }{a^{n} } = a^{(m-n)} ]

= m^{(-7-14)} n^{(14-(-28)} ÷ m^{(-15-10)} n^{(25-(-15)}

= m^{-21} n^{14+28} ÷ m^{-25} n^{25+15}

= \frac{m^{-21}n^{42}  }{m^{-25}n^{40}  }

= m^{(-21-(-25))} n^{(42-40)}

= m^{(-21+25)} n²

= m^{4} n² = m^{x} n^{y} , so x = 4 and y = 2

Then

m^{x-2y} = m^{4-2(2)} = m^{4-4} = m^{0} = 1 ← as required

6 0
3 years ago
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