If cos θ=(-5/13) and sin θ < 0, what is tan θ ? A. (12/5) B.(13/5) C. (-12/5) D.(√194/5)

1 answer:

mihalych1998 [28]3 years ago

5 0

If cos θ = (-5/13), then θ should be in quadrant II or III. The given says sin θ < 0, so θ should be in quadrant III. In this case, tan θ should be equal to number greater than zero. Hence we get sqrt of (13^2 - 5^2 ) equal to 12. tan θ should be equal to A 12/5.

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