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3 years ago

The difference of 5 and a number is at most 35

Mathematics

2 answers:

kvv77 [185]3 years ago

6 0

Answer:

x is less than or equal to 40

x < 41

Kisachek [45]3 years ago

5 0

Answer:

x is less than or equal to 40

x < 41

Step-by-step explanation:

I assume you are trying to find the number:

x - 5 < 36

You can add five to the right for

x < 41

You might be interested in

If -4(x-3)+5x=24, then x= what?

navik [9.2K]

The answer to this question would be x = 12, using pemdas.

4 0

3 years ago

t hits the square dartboard shown below at a random point. Find the probability that the dart lands in the shaded circular regio

masha68 [24]

Given:

Required:

To find the probability that the dart land will be in the shaded region.

Explanation:

Area of the circle is given by the formula:

$A=\pi r^2$

Where r = radius

Thus the area of the circular region

$\begin{gathered} =(3.14)\times(2)^2 \\ =3.14\times4 \\ =12.56\text{ square in.} \end{gathered}$

The area of the square is given by the formula:

$=(side)^2$

Thus the area of the given square

$\begin{gathered} =(6)^2 \\ =36\text{ square in.} \end{gathered}$

The probability of an event is given by the formula:

$P=\frac{number\text{ of possible outcomes}}{Total\text{ number of outcomes}}$

The probability that the dart land will be in the shaded region

$=\frac{Area\text{ of the shaded region}}{Area\text{ of the square}}$

Thus probability

$\begin{gathered} P=\frac{12.56}{36} \\ P=0.3488 \\ P=0.349 \end{gathered}$

Final answer:

Thus the probability that the dart land will be in the shaded region is 0.349.

6 0

1 year ago

Short Response

garik1379 [7]

Answer:

(a)2(89x+84)

(b) $2(89x+84-x^2\pi)$

Step-by-step explanation:

The dimensions of the larger rectangular field are:

Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain = $\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi$

Area of the Field that does not include the soccer field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

$=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)$

8 0

3 years ago

Pythagorean theorem help meeeeee!!

agasfer [191]

Answer:

Step-by-step explanation:

remember that the pythagorean theorem is a²+b²=c²

so this equation would be:

7²+24²=c²

solve the exponents

49 + 576 = c²

combine like terms

625 = c²

take the radical of each number

√625 = √c²

25 = c

have a lovely day <3

3 0

2 years ago

Match each equation with its solution set.

taurus [48]

Answer:

1- The solution of I2x + 5I = 9 is {-7 , 2}

2- The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- The solution of I5 - xI = 6 is {-1 , 11}

4- The solution of I6x - 8I + 7 = 5 is ∅

5- The solution of Ix + 3I = 12 is {-15 , 9}

6- The solution of Ix - 3I = -12 is ∅

Step-by-step explanation:

* At first lets explain the meaning of IxI = a

- If IxI = a ⇒ then x = a or x = -a

- IxI never give a negative answer, because IxI means the

magnitude of x is always positive

Ex: I-2I is 2

* Now lets find the solution of each equation

1- ∵ I2x + 5I = 9

∴ 2x + 5 = 9 ⇒ subtract 5 from both sides

∴ 2x = 4 ⇒ divide both sides by 2

∴ x = 2

∴ 2x + 5 = -9 ⇒ subtract 5 from both sides

∴ 2x = -14 ⇒ divide both sides by 2

∴ x = -7

* The solution of I2x + 5I = 9 is {-7 , 2}

2- ∵ I2x + 7I + 2 = 11 ⇒ Subtract 2 from both sides

∴ I2x + 7I = 9

∴ 2x + 7 = 9 ⇒ subtract 7 from both sides

∴ 2x = 2 ⇒ divide both sides by 2

∴ x = 1

∴ 2x + 7 = -9 ⇒ subtract 7 from both sides

∴ 2x = -16 ⇒ divide both sides by 2

∴ x = -8

* The solution of I2x + 7I + 2 = 11 is {-8 , 1}

3- ∵ I5 - xI = 6

∴ 5 -x = 6 ⇒ subtract 5 from both sides

∴ -x = 1 ⇒ divide both sides by -1

∴ x = -1

∴ 5 -x = -6 ⇒ subtract 5 from both sides

∴ -x = -11 ⇒ divide both sides by -1

∴ x = 11

* The solution of I5 - xI = 6 is {-1 , 11}

4- ∵ I6x - 8I + 7 = 5 ⇒ Subtract 7 from both sides

∴ I6x - 8I = -2

- I I never give negative answer

* The solution of I6x - 8I + 7 = 5 is ∅

5- ∵ Ix + 3I = 12

∴ x + 3 = 12 ⇒ subtract 3 from both sides

∴ x = 9

∴ x + 3 = -12 ⇒ subtract 3 from both sides

∴ x = -15

* The solution of Ix + 3I = 12 is {-15 , 9}

6- ∵ Ix - 3I = -12

- I I never give negative answer

* The solution of Ix - 3I = -12 is ∅

4 0

3 years ago