3 years ago

What is the equation for a circle with a radius of 10 and a center at (11, -2)?

1 answer:

7 0

The equation of a circle with centre (a, b) and radius r is (x - a)^2 + (y - b)^2 = r^2.
So here it is:
(x-11)^2 + (y+2)^2 = 100

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What are the roots of the equation? x^2+24=14×

defon

$\begin{gathered} x^2+24=14x \\ x^2-14x+24=0 \end{gathered}$

Therefore,

$\begin{gathered} x^2-14x+24=0 \\ x^2-2x-12x+24=0 \\ x(x-2)-12(x-2)=0 \\ (x-2)(x-12)=0 \\ x=2 \\ or\text{ } \\ x=12 \end{gathered}$

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1 year ago

Two equations are given below:

astraxan [27]

A - 3b = 4
a = b -2

(b - 2) - 3b = 4
b - 2 - 3b = 4
-2b = 4 + 2
-2b = 6
b = 6/-2
b = -3

a = b - 2
a = -3 -2
a = -5

to check: a = -5 ; b = -3 ⇒ (-5,-3)
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4 = 4

4 0

3 years ago