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Elena L [17]
3 years ago
12

A jet plane traveling at 450 mph overtakes a propeller plane traveling at 250 mph that had a 3​-hour head start. How far from th

e starting point are the​ planes?
Mathematics
2 answers:
Anon25 [30]3 years ago
8 0
It's suppose to add 450mph+250mph=700 then divide 3 hours=233.3
vodka [1.7K]3 years ago
8 0

Answer:

1687.5 miles

Step-by-step explanation:

Given: A jet plane traveling at 450 mph overtakes a propeller plane traveling at 250 mph that had a 3​-hour head start.

To Find: How far from the starting point are the​ planes

Solution:

Speed of jet plane = 450 \text{mph}

speed of Propeller plane = 250 \text{mph}

Distance travelled by propeller plane in 3 hours head start = \text{speed of propeller plane}\times\text{time}

                                              = 250\times3 = 750 \text{miles}

Distance to be travelled by jet plane to overtake propeller plane =  \text{distance between both planes}

                                                       750  \text{miles}

Relative speed of both planes = \text{Speed of jet plane}-\text{speed of propeller plane}

                                                    450-250=200 \text{mph}

Time taken by jet plane to overtake propeller plane =  

                                         \frac{\text{Distance between both planes}}{\text{relative speeds of planes}}

                                                    \frac{750}{200}=\frac{15}{4} \text{hours}

total distance travelled by plane = \text{Time taken by jet plane to overtake propeller plane}\times\text{speed of jet plane }

                                                       450\times\frac{15}{4}=1687.5 \text{miles}

planes are 1687.5 \text{miles} far from starting point.

                                                                                                                                                                                   

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