Only AAS cannot prove this.
So the answer will be A.
Answer:
The profit will be maximum on x = 250.
Step-by-step explanation:
From the given information:
Revenue = 1500x - x²
Cost = 1500 + 1000x
As we know that
Profit = Revenue - Cost ; Let say it equation 1
Then after putting the values of revenue and cost in equation 1 we have:
Profit = (1500x - x²) - (1500 + 1000x)
Profit = 1500x - x² - 1500 - 1000x
Profit = -x² + 500x - 1500
We know that at the max or min the slope of the graph formed by the profit function will be zero, therefore we find the slope of profit function by taking the first derrivative w.r.t. x as under:
d(Profit)/dx = d/dx(-x² + 500x - 1500)
d(Profit)/dx = -2x + 500
By putting the above slope equal to zero we get:
d(Profit)/dx = -2x + 500 = 0
-2x + 500 = 0
-2x = -500
x = 250
Therefore it is concluded that the profit will be maximum when x will be equal to 250.
Step-by-step explanation:
x^2+x-6006=0
x^2+78x-77x-6006=0
x(x+78)-77(x+78)=0
(x-77)(x+78)=0
=>x=77 or x=78
Answer:
The answer is $28,620.
Step-by-step explanation:
$53,000 * 2.7% = 1431
$1,431 * 20 = $28,620
Hope this helped you!!!
<em>i think it's just simply</em> y - 7 <em>?</em>
