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Andrei [34K]
3 years ago
12

You have two rectangular prisms (Prism A and Prism B). Prism A has the following dimensions: length x, width y, and height z. Pr

ism B is made by multiplying each dimension of Prism A by a factor of m, where m >0.
(a) Write a paragraph proof to show that the surface area of Prism B is 2 times the surface area of Prism A.

(b) Write a paragraph proof to show that the volume of Prism B is 3 times the volume of Prism A.
Mathematics
1 answer:
noname [10]3 years ago
3 0

Answer:

Part A) The surface area of prism B is equal to the surface area of prism A multiplied by the scale factor (m) squared  

Part B) The Volume of prism B is equal to the Volume of prism A multiplied by the scale factor (m) elevated to the cube

Step-by-step explanation:

Part A) we know that

The scale factor is equal to m

The surface area of the prism is equal to

S=2B+Ph

where

B is the area of the base

P is the perimeter of the base

h is the height of the prism

we have

Prism A

B=xy\ units^{2}

P=2(x+y)\ units

h=z\ units

substitute

SA=[2(xy)+2(x+y)z]\ units^{2}

Prism B

B=(mx)(my)=(xy)m^{2}\ units^{2}

P=2(mx+my)=2m(x+y)\ units

h=mz\ units

substitute

SB=[2(xym^{2})+2m(x+y)mz]\ units^{2}

SB=[2(xym^{2})+2m^{2}(x+y)z]\ units^{2}

SB=m^{2}[2(xy)+2(x+y)z]\ units^{2}

therefore

The surface area of prism B is equal to the surface area of prism A multiplied by the scale factor (m) squared      

Part B) we know that

The volume of the prism is equal to

V=Bh

where

B is the area of the base

h is the height of the prism

we have

Prism A

B=xy\ units^{2}

h=z\ units

substitute

VA=[(xyz]\ units^{3}

Prism B

B=(mx)(my)=(xy)m^{2}\ units^{2}

h=mz\ units

substitute

VB=[(xym^{2})mz]\ units^{3}

VB=[(xyzm^{3})]\ units^{3}

therefore

The Volume of prism B is equal to the Volume of prism A multiplied by the scale factor (m) elevated to the cube  

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Can someone help me thx
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Answer: 118



Explanation:

Since ∠A=∠ADB: ∠ADB=61°. The sum of the interior angles of any triangle is 180°, thus:

61°+61°= 122
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Since triangle BCD is an equilateral triangle, all the interior angles are the same:

180/3=60
∠DBC=60°
∠BCD=60°
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Since angles DBC and DBA make up angle ABC, just simply add the two angles together:

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Answer: y-32+4y

Step-by-step explanation:

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The sum of two numbers is twelve. One number is eight less than the other. Find the numbers.
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Find the distance between two points: (5,3),(8,5)​
kozerog [31]

Answer:

\displaystyle\boxed{\rm \: Distance= \underline{\underline{\sqrt{13}}}}

<em>OR </em><em>in </em><em>Decimal</em>,

\boxed{\rm \: Distance=\underline{\underline{3.605}}}

Step-by-step explanation:

<u>Given:</u>

Two points, that is (5,3) & (8,5)

<u>To Find:</u>

The Distance of the two given points

<u>Solution:</u>

To Find the distance between two points, we will use the <u>distance</u> <u>formula</u>, i.e. :

\boxed{ \rm \: Distance =  \sqrt{(x_2 - x_1) {}^{2}  + (y_2 - y_1) {}^{2} } }

According to the Question,

\rightarrow \:  \rm \: x_2 = 8

\rightarrow \:  \rm \: x_1 = 5

\rightarrow \:  \rm \: y_2 = 5

\rightarrow \:  \rm \: y_1 = 3

Now Substitute the values on the formula of Distance and then Simplify:

\rm \: Distance= \sqrt{(8 - 5 )^{2}  + (5 - 3) {}^{2} }

<em>[Follow PEMDAS rule while simplifying]</em>

\rm \: Distance= \sqrt{3 {}^{2}  + 2 {}^{2} }

\rm \: Distance= \sqrt{(3 \times 3) + (2 \times 2)}

\rm \:  Distance= \sqrt{9 + 4}

\rm \: Distance= \sqrt{13}

\rm \: Distance= {3.605}

Hence, the distance between the two given points would be \sqrt{13} or 3.605.

\rule{225pt}{2pt}

I hope this helps!

Have a good day! :)

<em>[Desmos Graph solution is attached]</em>

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