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ankoles [38]
3 years ago
12

9x^2+7x-1 degree and classify

Mathematics
1 answer:
IceJOKER [234]3 years ago
6 0
<h2>f</h2><h2>(</h2><h2>x</h2><h2>)</h2><h2>=</h2><h2>x</h2><h2>3</h2><h2>−</h2><h2>9</h2><h2>x</h2><h2>2</h2><h2>+</h2><h2>24</h2><h2>x</h2><h2>−</h2><h2>10</h2><h2>Taking first derivative of</h2><h2> </h2><h2> </h2><h2>f</h2><h2>(</h2><h2>x</h2><h2>)</h2><h2>f</h2><h2>′</h2><h2>(</h2><h2>x</h2><h2>)</h2><h2>=</h2><h2>3</h2><h2>x</h2><h2>2</h2><h2>−</h2><h2>18</h2><h2>x</h2><h2>+</h2><h2>24</h2><h2>For finding critical points substituting</h2><h2> </h2><h2>f</h2><h2>′</h2><h2>(</h2><h2>x</h2><h2>)</h2><h2>=</h2><h2>0</h2><h2>f</h2><h2>′</h2><h2>(</h2><h2>x</h2><h2>)</h2><h2>=</h2><h2>0</h2><h2> </h2><h2>⇒</h2><h2>3</h2><h2>x</h2><h2>2</h2><h2>−</h2><h2>18</h2><h2>x</h2><h2>+</h2><h2>24</h2><h2>=</h2><h2>0</h2><h2> </h2><h2>⇒</h2><h2>3</h2><h2>(</h2><h2>x</h2><h2>2</h2><h2>−</h2><h2>6</h2><h2>x</h2><h2>+</h2><h2>8</h2><h2>)</h2><h2>=</h2><h2>0</h2><h2>(</h2><h2>x</h2><h2>−</h2><h2>4</h2><h2>)</h2><h2>(</h2><h2>x</h2><h2>−</h2><h2>2</h2><h2>)</h2><h2>=</h2><h2>0</h2><h2>After solving the value of x is</h2><h2>x</h2><h2>=</h2><h2>2</h2><h2>,</h2><h2>4</h2><h2>Thus critical points at</h2><h2> </h2><h2> </h2><h2>x</h2><h2>=</h2><h2>2</h2><h2>,</h2><h2>4</h2>
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\sqrt[3]{x^2-8}=2 \\ x^2-8=2^3=8  \\ x^2=16 \\  \\ \boxed{x=4 \ or \ -4}
6 0
3 years ago
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<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2
PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given Trigonometric expression is

\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }

So, on rationalizing the denominator, we get

\rm \:  =  \: \dfrac{sin\theta }{1 + cos\theta }  \times \dfrac{1 - cos\theta }{1 - cos\theta }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}}

So, using this, we get

\rm \:  =  \: \dfrac{sin\theta (1  -  cos\theta )}{1 -  {cos}^{2}\theta  }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {sin}^{2}x +  {cos}^{2}x = 1}}}

So, using this identity, we get

\rm \:  =  \: \dfrac{sin\theta (1 -  cos\theta )}{{sin}^{2}\theta  }

\rm \:  =  \: \dfrac{1 - cos\theta }{sin\theta }

<u>Hence, </u>

\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta }   =  \: \dfrac{1 - cos\theta }{sin\theta } }}} \\

3 0
2 years ago
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Simplify this expression HELP ASAP
Sergio039 [100]

Answer:

B

Step-by-step explanation:

Noting the following rule of radicals

\sqrt{a} × \sqrt{b} = \sqrt{ab}

Given

(\sqrt{2} + \sqrt{3})( \sqrt{5} - \sqrt{7} )

Each term in the second factor is multiplied by each term in the first factor

= \sqrt{2}(\sqrt{5} - \sqrt{7}) + \sqrt{3}(\sqrt{5} - \sqrt{7}) ← distribute parenthesis

= \sqrt{10} - \sqrt{14} + \sqrt{15} - \sqrt{21}

8 0
3 years ago
What is the value of x using the Pythagorean theorem?
Vesnalui [34]
A^2+b^2= c^2

Plug in the points. the longest side is always c.

95.2^2+ b^2= 168^2.

Square the numbers.

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Subtract 9063.04 on both sides.

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Find the square root. 

b= 138.423119456

Or, b= 138.4 (rounded down)

I hope this helps!
~kaiker
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dybincka [34]

Answer:

No more

Step-by-step explanation:

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