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3 years ago

Which expressions are equivalent to (d^1/8) ^5

Mathematics

1 answer:

Tanya [424]3 years ago

8 0

Answer:

Formula used : (a^m)^n = a^(m×n)

$→{( {d}^{ \frac{1}{8} }) }^{5} = {d}^{( \frac{1}{8}\times 5) } = \boxed{{d}^{ \frac{5}{8} } }✓ \\$

d^⅝ is the right answer.

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Vitek1552 [10]

Answer:

Given :

→x-y=12

→xy= 3²

Equation formed:

${(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy$

Step by step explanation:

${(12)}^{2} = {x}^{2} + {y}^{2} - 2 \times 9 \\ 144 + 18 = {x}^{2} + {y}^{2} \\ = 162$

hope it helped you:)

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4 years ago

Which of the following is equivalent to 5 · (7 · 4)? *

MariettaO [177]

B because you multiply 7 times 4 that’s 28 then times 5 that’s 140 so for b you do 5 times 7 that’s 35 then times 4 that’s 140 so b is the correct answer, hope it helps

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3 years ago

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VikaD [51]

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3 years ago

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write the product of the expression 5^4 * 5^-7 using a positive exponent, then write the product using a negative exponent

pav-90 [236]

Answer with positive exponent = $\left(\frac{1}{5}\right)^3$ or $\frac{1}{5^3}$

Answer with negative exponent = $5^{-3}$

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Explanation:

The rule we use is

$a^b*a^c = a^{b+c}$

If we multiply two exponential expressions with the same base, then we add the exponents.

The base for each is 5. The exponents 4 and -7 add to -3.

This means

$5^4*5^{-7} = 5^{4+(-7)} = 5^{-3}$

To convert to a positive exponent, we apply the reciprocal to the base. We go from 5, aka 5/1, to 1/5.

So, $5^{-3} = \left(\frac{1}{5}\right)^3 = \frac{1^3}{5^3} = \frac{1}{5^3}$

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sp2606 [1]

The answer is B) 100%

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3 years ago

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