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Aleks04 [339]
3 years ago
8

Which expressions are equivalent to (d^1/8) ^5

Mathematics
1 answer:
Tanya [424]3 years ago
8 0

Answer:

Formula used : (a^m)^n = a^(m×n)

→{( {d}^{ \frac{1}{8} }) }^{5}  =  {d}^{( \frac{1}{8}\times 5) }  =   \boxed{{d}^{ \frac{5}{8} } }✓ \\

  • <u>d^⅝</u> is the right answer.
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Y’all what’s this I’m so confused help
Snowcat [4.5K]

Answer:

x = 66

Step-by-step explanation:

√(x - 2) + 3 = 11

Subtract 3 from both sides:  √(x - 2) = 8

Square both sides:                   x - 2 = 64

Add 2 to both sides:                      x = 66

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3 years ago
Solve for x: x - 9 = 15<br><br> A. 6<br> B. 24<br> C. -24<br> D. -6
Oduvanchick [21]

Answer:

X = 24

Step-by-step explanation:

Add 9 To Both Sides

X - 9 + 9 = 15 + 9

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3 years ago
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skad [1K]

Don't let it get to ya. If they didn't think you're capable of answering this question, they wouldn't ask you. So they know your abilities better than you do.

We don't know the unknown number, so in order to discuss it, we have to give it some kind of a name. We could call it 'x', 'y', 'Ana, 'Q', or 'Ralph'. Let's call it 't'.

The unknown number . . . . . t

Five times the number . . . . . 5t

Nine less than five times the number . . . . . 5t - 9 . Hold on to this quantity.

Twice the number . . . . . 2t .

Three more than twice the number . . . . . 2t + 3. Hold on to this quantity too.

The question says that these two quantities are equal. So the equation is

5t - 9 = 2t + 3 . This is the equation in both choices 'c' and 'd' . I guess we'll have to solve it to find out which choice is the correct one.

The equation is . . . . . 5t - 9 = 2t + 3

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3 years ago
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Eduardwww [97]
The identity property of addition states that a + 0 = a

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shtirl [24]

Answer:

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Step-by-step explanation:

Shading is <em>below</em> the <em>solid</em> line, so the appropriate relation symbol is "less than or equal to" (≤).

Shading is <em>below</em> when y values less than those on the line are part of the solution set.

The line is <em>solid</em> when it is part of the solution set (dashed, otherwise). It is part of the solution set when y-values <em>equal to</em> those on the line are solutions to the inequality.

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