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2 years ago

8

Which expressions are equivalent to (d^1/8) ^5

1 answer:

Tanya [424]2 years ago

8 0

Answer:

Formula used : (a^m)^n = a^(m×n)

$→{( {d}^{ \frac{1}{8} }) }^{5} = {d}^{( \frac{1}{8}\times 5) } = \boxed{{d}^{ \frac{5}{8} } }✓ \\$

<u>d^⅝</u> is the right answer.

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One base of a triangular prism has two sides that are 15 inches wide and 10 inches long what is the possible length for the thir

Tcecarenko [31]

18.03 inches
Put the dimensions into the pythagorean theorem, that will give you the answer.

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3 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

<u>Area of triangle ABD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

<u>Area of triangle BCD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

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3 years ago

A weather forecaster says the temperature will be about -5C “give or take” 10 degrees. What is the greatest possible temperature

bagirrra123 [75]

Minimum: -15C

Max: 5C

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2 years ago

Convert 9.56 into a percentage

Drupady [299]

9.56 can be split into 9 , 0.5 , and 0.06

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3 years ago

Read 2 more answers

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation $y=-16x^2+224x+121$ . We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute $y=0$ in our given equation as:

$0=-16x^2+224x+121$

Let us solve for x using quadratic formula.

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-224\pm\sqrt{224^2-4(-16)(121)}}{2(-16)}$

$x=\frac{-224\pm\sqrt{50176+7744}}{-32}$

$x=\frac{-224\pm\sqrt{57920}}{-32}$

$x=\frac{-224\pm240.66574}{-32}$

$x=\frac{-224+240.66574}{-32}, x=\frac{-224-240.66574}{-32}$

$x=\frac{16.66574}{-32}, x=\frac{-464.66574}{-32}$

$x=-0.520804375, x=14.520804375$

Upon rounding to nearest 100th of second, we will get:

$x\approx -0.52, x\approx 14.52$

Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.

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3 years ago

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