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Kruka [31]
3 years ago
15

3.

Mathematics
1 answer:
Lynna [10]3 years ago
3 0

Answer:

the answer is B {(0,-4),(2,6)(,4,16)

happy to help

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\large -6x+6y=6<br> \large 6x+3y=12
Kaylis [27]

Answer:

the solution of the system is:

x = 1 and y = 2.

Step-by-step explanation:

I suppose that we want to solve the equation:

-6*x + 6*y = 6

6*x + 3*y = 12

To solve this, we first need to isolate one of the variables in one of the equations.

Let's isolate y in the first equation:

6*y = 6 + 6*x

y = (6 + 6*x)/6

y = 6/6 + (6*x)/6

y = 1 + x

Now we can replace this in the other equation:

6*x + 3*(1 + x) = 12

6*x + 3 + 3*x = 12

9*x + 3 = 12

9*x = 12 - 3 = 9

x = 9/9 = 1

Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.

y = 1 + (1)  = 2

Then the solution of the system is:

x = 1 and y = 2.

6 0
3 years ago
The sequence a, = 2, 4, 8, 16, 32, ... is the same as the sequence ay = 2,
blondinia [14]

Answer:

TRUE

Step-by-step explanation:

TRUE

a_1 = 2

a_n = 2*(an_1)

if we start with 2, we would get

a_2 = 2*(a_1) = 2*(2) = 4

a_3 = 2*(a_2) = 2*(4) = 8

a_4 = 2*(a_3) = 2*(8) = 16

a_5 = 2*(a_4) = 2*(16) = 32

.

.

.

and so on

4 0
3 years ago
rotation of 90 degrees counterclockwise about the origin, point O, then a reflection across the x-axis reflection across the y-a
SpyIntel [72]

Answer:

The point O can be (x,y)  or (-x,y) or (-x,-y) or ( x,-y) reason being that you haven't given point O lies in which quadrant.

Rotation through 90° counter clockwise

(x,y) = (-y,x)

(-x,y)=(-y,-x)

(-x,-y)=(y,-x)

(x,-y) =(y,x)

Then Reflection across X axis has taken place.

(-y,x) = (-y,-x)

(-y,-x)=(-y,x)

(y,-x)=(y,x)

(y,x)=(y,-x)

Then a reflection across the y-axis has taken place.

(-y,-x)=(y,-x)

(-y,x) = (y,x)

(y,x) =(-y,x)

(y,-x)=(-y,-x)

Then a translation a units to the right and b units up has taken place.

(y,-x)=(y+a,-x+b)

(y,x) =(y+a, x+b)

(-y,x) =(-y+a,x+b)

(-y,-x)=(-y+a,-x+b)

Then a rotation of 180 degrees counterclockwise about the origin has taken place.

(y+a,-x+b)=[-(y+a),-(-x+b)]

(y+a, x+b)=[- (y+a), -(x+b)]

(-y+a,x+b)=[-(-y+a),-(x+b)]

(-y+a,-x+b) =[-(-y+a),-(-x+b)]

Now Again a reflection across the Y axis has taken place.

[-(y+a),-(-x+b)]=[(y+a),-(-x+b)]

[-(y+a),-(x+b)]=[(y+a),-(-x+b)]

[-(-y+a),-(x+b)]=[(-y+a),-(x+b)]

[-(-y+a),-(-x+b)]=[(-y+a),-(-x+b)]

Totally depends on value of a and b on which quadrant these point lies.



7 0
3 years ago
Find the measure of angle
leva [86]
51,
Find angle y first by setting it equal to 180
With its adjacent angles. Then solve for x by triangle angles
8 0
3 years ago
Evaluate 2/5g + 3h - 6 when g = 10 and z = 6
poizon [28]

Answer:

16

Step-by-step explanation:

Well first we need to plug in 10 for g and 6 for h.

2/5(10) + 3(6) - 6

4 + 18 - 6

22 - 6

16

<em>Thus,</em>

<em>the answer is 16.</em>

<em />

<em>Hipe this helps :)</em>

4 0
3 years ago
Read 2 more answers
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