Answer:
A. -12 meters
B. 28 meters
C. 40 meters
Step-by-step explanation:
The surface of the ocean would be 0.
Taking this into account, 12 meters below would be 0 - 12, which is -12. Therefore A's elevation would be -12.
For the sea bird, 28 meters above the surface, which is again 0, would be 0 + 28. B's elevation is 28.
Since the fish is 12 meters below the surface and the sea bird is 28 meters above the surface, simply add the two numbers up to get a total of 40 meters. C would be 40 meters.
27 divided by 15 is 1.8, so that should be the correct answer.
Answer:
x = 9
TH = 12
Step-by-step explanation:
since TM is half of HM, the equation is:
2(21 - x) = 3x - 3
42 - 2x = 3x - 3
45 = 5x
x = 9
TH = 21 - x
TH = 21 - 9
TH = 12
Answer:
x^2+2x-5 - 1/x
Step-by-step explanation:
f(x)=1/x
g(x)=x^2+2x-5
(g-f)(x) = x^2+2x-5 - 1/x
a. By the fundamental theorem of calculus, the velocity function is
![v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du](https://tex.z-dn.net/?f=v%28t%29%3Dv%280%29%2B%5Cdisplaystyle%5Cint_0%5Eta%28u%29%5C%2C%5Cmathrm%20du)
The particle starts at rest, so
, and we have
![v(t)=\displaystyle\int_0^t6\cos u\,\mathrm du=6\sin u\bigg|_0^t=6\sin t](https://tex.z-dn.net/?f=v%28t%29%3D%5Cdisplaystyle%5Cint_0%5Et6%5Ccos%20u%5C%2C%5Cmathrm%20du%3D6%5Csin%20u%5Cbigg%7C_0%5Et%3D6%5Csin%20t)
Then the position function is
![x(t)=\displaystyle x(0)+\int_0^tv(u)\,\mathrm du](https://tex.z-dn.net/?f=x%28t%29%3D%5Cdisplaystyle%20x%280%29%2B%5Cint_0%5Etv%28u%29%5C%2C%5Cmathrm%20du)
with
, so
![x(t)=6+\displaystyle\int_0^t6\sin u\,\mathrm du=6-6\cos u\bigg|_0^t=12-6\cos t](https://tex.z-dn.net/?f=x%28t%29%3D6%2B%5Cdisplaystyle%5Cint_0%5Et6%5Csin%20u%5C%2C%5Cmathrm%20du%3D6-6%5Ccos%20u%5Cbigg%7C_0%5Et%3D12-6%5Ccos%20t)
b. The particle is at rest whenever
; this happens for
![6\sin t=0\implies \sin t=0\implies t=n\pi](https://tex.z-dn.net/?f=6%5Csin%20t%3D0%5Cimplies%20%5Csin%20t%3D0%5Cimplies%20t%3Dn%5Cpi)
where
is any integer.