Question

In this triangle, what is the value of x?

Answer 1

Use the trigonometric function.

$\cos x^o=\dfrac{28}{72}\\\\\cos x^o\approx0.3889\to x^o\approx67.1^o$

Answer 2

Answer:

x = 67.10° is the answer.

Step-by-step explanation:

The given triangle is a right angle triangle in which measure of angle is given as x°. Adjacent side (Base) of the angle x is 28 ft and largest side of the triangle (Hypotenuse) is of 72 ft.

We have to the value of x.

Now we find the cosine of angle x

cosx = $\frac{\text{Base}}{\text{Hypotenuse}}$

cosx = $\frac{28}{72}$

cosx = $\frac{7}{18}$ = 0.389

x = $cos^{-1}(0.389)$

x = 67.10°

angle x = 67.10° is the answer.