6.5 x 10 to the 10th power.
Answer:

Where k represent the number of wave
and
represent the angular frequency with T the period.
For this case we know tha T = 520 nm
And the angular frequency would be given by:

So then the possible anwer for this case would be:
D.) y= sin pi/260 theta
Since is the only option with satisfy the general equation of a wave.
Step-by-step explanation:
Since the sine function can be used to model light waves we can use the following general expression:

Where k represent the number of wave
and
represent the angular frequency with T the period.
For this case we know tha T = 520 nm
And the angular frequency would be given by:

So then the possible anwer for this case would be:
D.) y= sin pi/260 theta
Since is the only option with satisfy the general equation of a wave.
F x equals X Plus x squared minus 10
9514 1404 393
Answer:
A. 12.28 km²
Step-by-step explanation:
The area of the figure is the sum of the areas of its parts. The area of the triangular part is ...
A = 1/2bh
A = 1/2(3 km)(4 km) = 6 km²
__
The area of the semicircular part is ...
A = 1/2πr²
A = 1/2(3.14)(2 km)² = 6.28 km²
__
Then the area of the figure is ...
6 km² + 6.28 km² = 12.28 km²